Hello!
To find the equation of a line parallel to y = 3x - 3 and passing through the point (4, 15), we need to know that if two lines are parallel, then their slopes are equivalent.
This means that we create a new equation in slope-intercept form, which includes the original slope, which is equal to 3.
In slope-intercept form, we need a y-intercept. So, we would substitute the given ordered pair into the new equation with the same slope and solve.
Remember that slope-intercept form is: y = mx + b, where m is the slope and b is the y-intercept.
y = 3x + b (substitute the ordered pair (4, 15))
15 = 3(4) + b (simplify)
15 = 12 + b (subtract 12 from both sides)
3 = b
Therefore, the equation for the line parallel to the line y = 3x - 3, and passing through the point (4, 15) is y = 3x + 3.
Answer:
x= -1 or x = -2
Step-by-step explanation:
Your equation:
(x−3)^3−(x−1)^3+7x^2=7(3x−4)
Step 1: Simplify both sides of the equation.
x^2+24x−26=21x−28
Step 2: Subtract 21x-28 from both sides.
x^2+24x−26−(21x−28)=21x−28−(21x−28)
x^2+3x+2=0
Step 3: Factor left side of equation.
(x+1)(x+2)=0
Step 4: Set factors equal to zero.
x+1=0 or x+2=0
which equals to x=−1 or x=−2
465•10-5
(That -5 is suppose to be an exponent
D)5,400,000 Is your answer....
Answer:C. 2/3 cm/s
Step-by-step explanation:
