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kondaur [170]
3 years ago
5

Find the area of a square whose vertices have the coordinates (3,6), (3, 1), (-2, 1), and (-2,6)​

Mathematics
1 answer:
Eduardwww [97]3 years ago
3 0

Answer:

25 square units

Step-by-step explanation:

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(geometry) please look at attached image and help me with this question!
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Answer:

  m∠AEC = 139°

Step-by-step explanation:

To make the equations easier to write, let's say all measures are in degrees, and define ...

  p = m∠AEB = 11x -12

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Then ...

  p + 2q = 180

  (11x -12) + 2(4x +1) = 180

  19x -10 = 180 . . . . . . . . . . . . collect terms

  19x = 190 . . . . . . . . add 10

  x = 10 . . . . . . . . . . . divide by 19

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The angle of interest is ...

  m∠AEC = p +q = 98 +41

  m∠AEC = 139 . . . . degrees

8 0
3 years ago
A =4 <br> 5<br><br> b =3<br> 2<br> Work out a - 2b as a column vector.
Umnica [9.8K]

Answer:

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Step-by-step explanation:

See explanation in the attachment.

3 0
3 years ago
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URGENT WILL MARK BRAINLIEST
allochka39001 [22]

Explanation:

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Then the triangles ADB and ADC are congruent by the HL congruence theorem.

Angles B and C are corresponding parts of congruent triangles, so are congruent by CPCTC.

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