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kondaur [170]
3 years ago
5

Find the area of a square whose vertices have the coordinates (3,6), (3, 1), (-2, 1), and (-2,6)​

Mathematics
1 answer:
Eduardwww [97]3 years ago
3 0

Answer:

25 square units

Step-by-step explanation:

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Hank the handy man charges a flat fee of $75 per visit, plus $45 per hour or fracrion of an hour
Taya2010 [7]
<h3> - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - </h3>

➷ Hank charges $75 for a visit plus $45 per hour.

Therefore, for an hour, Hank would charge $120 as 75 + 45 = 120

Mr Fixit:

As it is for one hour, we look at the first function because the time is 'less than or equal to an hour'.

Mr Fixit would charge $95 for an hour.

Therefore, Hank charges $25 more than Mr Fixit.

➶Hope This Helps You!

➶Good Luck :)

➶Have A Great Day ^-^

↬ Hannah ♡

4 0
3 years ago
Read 2 more answers
What is the distance between the points (-5, 10) and (-5, 2)?
Alona [7]
8 units hope I helped
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3 years ago
susie reads 4 pages in 5 minutes at this rate how many pages will she have read in 35 minutes set up a Proportion and solve
belka [17]

Answer:

20

Step-by-step explanation:

i did this on a hw equation

6 0
2 years ago
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8.) A line passes through the points (k, 4) and (3, -6). The line is perpendicular to
amm1812

Answer:

K = 43

Step-by-step explanation:

We'll begin by determining the gradient of the equation 5y + 4x = 8. This can be obtained as follow:

5y + 4x = 8

Rearrange

5y = 8 – 4x

5y = –4x + 8

Comparing 5y = –4x + 8 with y = mx + c, the gradient m is –4

Next, we shall determine the gradient of the line perpendicular to the line with equation 5y = 8 – 4x.

This can be obtained as follow:

For perpendicular lines, their gradient is given by:

m1 × m2 = – 1

With the above formula, we can obtain the gradient of the line as follow:

m1 × m2 = – 1

m1 = –4

–4 × m2 = – 1

Divide both side by –4

m2 = –1/–4

m2 = 1/4

Finally, we shall determine the value of k as follow:

Coordinate => (k, 4) and (3, –6)

x1 coordinate = k

y1 coordinate = 4

x2 coordinate = 3

y2 coordinate = –6

Gradient (m) = 1/4

m = (y2 – y1) / (x2 – x1)

1/4 = (–6 – 4) / (3 – K)

1/4 = –10 /(3 – K)

Cross multiply

3 – K = 4 × –10

3 – K = –40

Collect like terms

– K = – 40 –3

–k = –43

Divide both side by – 1

K = –43/–1

k = 43

3 0
3 years ago
Solve.
andriy [413]
K/6 + 8 = 19
       -8     -8
-------------------
k/6 = 11
×6      ×6
---------------
k = 66
7 0
3 years ago
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