All categories

3 years ago

URGENT WILL MARK BRAINLIEST

Mathematics

1 answer:

allochka39001 [22]3 years ago

5 0

Explanation:

Draw altitude AD to segment BC such that point D is on BC. This creates right triangles ADB and ADC.

Hypotenuses AB and AC are given as congruent. Leg AD in each triangle is congruent to itself by the reflexive property of congruence.

Then the triangles ADB and ADC are congruent by the HL congruence theorem.

Angles B and C are corresponding parts of congruent triangles, so are congruent by CPCTC.

You might be interested in

How do i simplify 100.00 - 48.37

Andrej [43]

Answer:

51.63

Step-by-step explanation:

100.00

- 48.37

______

51.63

______

5 0

3 years ago

How would I solve this agai n

Svetllana [295]

Answer:

The area is 35 inches

Step-by-step explanation:

You will need to cut the shape into 3 parts

the 3 by 3

2 by 5

and 4 by 4

after that you multiply the numbers to get the area of the 3 parts.

The final step is to add them all up

( if you have more problems message me)

3 0

2 years ago

Read 2 more answers

7400 dollars is placed in an account with an annual interest

Anastasy [175]

Answer:

Step-by-step explanation:

We have the following equation for compounding annual interest

AV=PV(1+i)ⁿ

We have

19200=7400(1+.06)ⁿ

Solve for n

divide both sides by 7400

2.594=(1.06)ⁿ

then use the following rule for exponents

$x^y=z\\log_xz=y$

which means that

$log_{1.06}2.594=n$

Solve and get

16.362

which rounds to 17

6 0

3 years ago

Please help me. Somebody! I need help.

kogti [31]

Answer:

https://www.imsdb.com/scripts/Shrek.html

Step-by-step explanation: Follow this link. DO it no ballz

5 0

3 years ago

Show how to find the roots (zeros) of the function in the picture below.

Vikki [24]

Answer:

The roots (zeros) of the function are:

$x=5,\:x=-8$

Step-by-step explanation:

Given the function

$f\left(x\right)=x^2+3x-40$

substitute f(x) = 0 to determine the zeros of the function

$0=x^2+3x-40$

First break the expression x² + 3x - 40 into groups

x² + 3x - 40 = (x² - 5x) + (8x - 40)

Factor out x from x² - 5x: x(x - 5)

Factor out 8 from 8x - 40: 8(x - 5)

Thus, the expression becomes

$0=x\left(x-5\right)+8\left(x-5\right)$

switch the sides

$x\left(x-5\right)+8\left(x-5\right)=0$

Factor out common term x - 5

$(x - 5) (x + 8) = 0$

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

$x-5=0\quad \mathrm{or}\quad \:x+8=0$

Solve x - 5 = 0

x - 5 = 0

adding 5 to both sides

x - 5 + 5 = 0 + 5

x = 5

solve x + 8 = 0

x + 8 = 0

subtracting 8 from both sides

x + 8 - 8 = 0 - 8

x = -8

Therefore, the roots (zeros) of the function are:

$x=5,\:x=-8$

6 0

2 years ago