The question is incomplete. Here is the complete question.
Semicircles and quarter circles are types of arc lengths. Recall that an arc is simply part of a circle. we learned about the degree measure of an ac, but they also have physical lengths.
a) Determine the arc length to the nearest tenth of an inch.
b) Explain why the following proportion would solve for the length of AC below: 
c) Solve the proportion in (b) to find the length of AC to the nearest tenth of an inch.
Note: The image in the attachment shows the arc to solve this question.
Answer: a) 9.4 in
c) x = 13.6 in
Step-by-step explanation:
a) 
, where:
r is the radius of the circumference
mAB is the angle of the arc
arc length = 
arc length = 
arc length = 9.4
The arc lenght for the image is 9.4 inches.
b) An <u>arc</u> <u>length</u> is a fraction of the circumference of a circle. To determine the arc length, the ratio of the length of an arc to the circumference is equal to the ratio of the measure of the arc to 360°. So, suppose the arc length is x, for the arc in (b):
c) Resolving (b):
x = 
x = 13.6
The arc length for the image is 13.6 inches.
Answer:
Step-by-step explanation:
Take one polynomial from the other means to perform the sub.traction of them. Recall that it is better to use grouping symbols when subtracting polynomials, so we get the signs right when combining like terms:
The indicated subtraction is: 
Make sure that before removing the grouping symbol (parenthesis) that is preceded by a negative sign, we change the signs of every term inside it. Then combine like terms to get the final answer:
Which is the last option shown in the question
0.875 as a fraction is 7/8 because 875/100 is equal to 7/8
28 pounds
35 (together) - 7 (sleeping bag)
Answer:
Step-by-step explanation:
sqrt(28): sqrt(4*7)
sqrt(4) = 2;
sqrt28)=2*sqrt(7)
sqrt(343): sqrt(7 * 7 * 7) = 7 * sqrt(7)
Note: the rule is if you have 3 equal primes under the root sign, you leave one, you throw one away, and you put one outside the root sign.
2 sqrt(63) = 2 sqrt(3*3*7) The above rule gets modified to throw 1 three away and take the other one outside the root sign.
2sqrt(63) = 2*3 sqrt(7)
Numerator: 2*sqrt(7) + 7sqrt(7) = 9sqrt(7)
9sqrt(7)
======
6 sqrt(7)
3/2
Note without brackets I cannot be certain that I have interpreted this correctly. The division only apply to sqrt(343) / 2 sqrt(63). If this is so please leave a note.
