Answer:
y = -3x -4
Step-by-step explanation:
A perpendicular line has a slope that is the negative reciprocal of that of the given line. When the equation starts out in standard form, a line with negative reciprocal slope can be written by swapping the x- and y-coefficients and negating one of them.
The given x- and y-coefficients have the ratio 1:-3, so we can use the coefficients 3 and 1 for our purpose.
The usual process of making the line go through a given point can be used. That is, we can translate the line from the origin to the desired point by subtracting the point coordinates from x and y. Then we have ...
3(x+3) +(y-5) = 0
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This is "an" equation. It is in no particularly recognizable form. It can be rearranged to the form y = mx + b:
3x +9 +y -5 = 0 . . . . . eliminate parentheses
y = -3x -4 . . . . . subtract terms that are not "y"
Answer:
10.7 feet
Step-by-step explanation:
The ladder, the ground and the wall form the shape of a right angled triangle as shown in the image below.
The hypotenuse of the triangle is 14 feet (length of ladder)
The base of the triangle is 9 feet long (the distance from the base of the ladder to the wall)
We need to find the height of the triangle. We can apply Pythagoras rule:
where hyp = hypotenuse
a = base of the triangle
b = height of the triangle
Therefore:
The wall reaches 10.7 feet high.
Answer:
1 5/6
Step-by-step explanation:
Do 2/3 x 2/1 because 2/1 = 2 and you get 1 1/3. Make 1 1/3 into 1 2/6 (1/3 = 2/6) and add 3/6 (1/2 = 3/6)
To determine the number of platelets present in the human body, we need a relation that would relate this value to the given value above which is the number of white blood cells. Fortunately, we are given a ratio of 30. So, we use this value as follows:
number of platelets/number of white blood cells = 30
number of platelets / <span>8×10^3 white blood cells = 30
number of platelets = 240000</span>
Answer:
C. Wright Mills
Step-by-step explanation:
was the American sociologist who strongly criticized the structural functionalist approach to sociology.
