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Sergio [31]
2 years ago
8

1. Mahammed bought 4 boxes of chocolates online. Postage was $10 and the total cost was $58. Let b represent the price of each b

ox.
​
Mathematics
1 answer:
suter [353]2 years ago
4 0

Answer:  $14.5

Step-by-step explanation: you divide 58 by 4 . each box is 14.5. total cost is $68 if you add postage

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1 b. 2 c. 3 d. 4 5(z + 1) = 3(z + 2) + 11 Solve for Z 
Roman55 [17]

Answer:

5z+5=3z+6

5z+3z=6+5

8z=11

z=11÷8

5 0
3 years ago
Can someone please send the answers to these questions with explanation? (Attachment) (30 POINTS)
Leto [7]

Answer:

Step-by-step explanation:

a) this graph is that of a parabola that opens up.  As is the case for all parabolas, the domain is the set of all real numbers.  The range begins with the smallest y-value, which is -4, extending upwards from there:  [-4, infinity)

b) this graph's shape most closely resembles that of a polynomial; as we move from left to right, y increases, reaches a local maximum, decreases to a local minimum, and then continues to increase with x.  As is the case for all polynomials, the domain is the set of all real numbers.  As we move from x = 0 to the left, y decreases without bound; from x ≥ 12 onward, y increases without bound; thus, the range is (-infinity, +infinity).

c) The graph represents a quarter of an ellipse for which x begins at -40 and ends at [4, -16].  Thus, the domain is [-40, 4].  By inspection we see that the smallest y value is -16 and the largest is 4; thus, the range is [-40, 4].

8 0
1 year ago
If x^2 + 1/x^2 = 18 , find the value of x^3-1/x^3​
astra-53 [7]

Step-by-step explanation:

hope this helps you dear friend.

6 0
3 years ago
Read 2 more answers
The nth term of a sequence is represented by 3n4−10/6n4+7 . What is the limit of the the nth term as n becomes increasingly larg
Cerrena [4.2K]

Answer:

<h3>1/2</h3>

Step-by-step explanation:

Given the limit of the function expressed as;

\lim_{n \to \infty} \frac{3n^4-10}{6n^4+7} \\

To take the limit, we nee to divide through by the highest power of n first

\lim_{n \to \infty} \frac{3n^4/n^4-10/n^2}{6n^4/n^4+7/n^4}\\= \lim_{n \to \infty} \frac{3-10/n^2}{6+7/n^4}\\= \frac{3-10/(\infty)^2}{6+7/(\infty)^4}\\= \frac{3-0}{6-0}\\= \frac{3}{6}\\ = \frac{1}{2}\\

Hence the limit of the the nth term as n becomes increasingly large is 1/2

3 0
3 years ago
Which point is a solution to the system of inequalities graphed here? y ≤ 2x + 2
Vlad [161]

Answer:

D) (5,0)

Step-by-step explanation:

-5x + 4 ≤ y

-25 + 5 ≤ 0

-20 ≤ 0

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0 ≤ 27

6 0
3 years ago
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