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DanielleElmas [232]
3 years ago
13

Lines y = -x+2 and y=x+1

Mathematics
1 answer:
nataly862011 [7]3 years ago
3 0

\\ \sf\Rrightarrow y=-x+2(1)

\\ \sf\Rrightarrow y=x+1(2)

Now

\\ \sf\Rrightarrow -x+2=x+1

\\ \sf\Rrightarrow -2x=-1

\\ \sf\Rrightarrow x=0.5

Put in eq(2)

\\ \sf\Rrightarrow y=0.5+1

\\ \sf\Rrightarrow y=1.5

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Which is the factorization of 8x2 13x – 6? (8x – 3)(x 2) (x – 6)(8x 1) (2x – 2)(4x 3) (4x – 1)(2x 6)
vagabundo [1.1K]

we have

8x^2+13x - 6

Equate the function to zero

8x^2+13x - 6=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

8x^2+13x = 6

Factor the leading coefficient

8(x^2+\frac{13}{8}x) = 6

Complete the square. Remember to balance the equation by adding the same constants to each side.

8(x^2+\frac{13}{8}x) = 6

8(x^2+\frac{13}{8}x+\frac{169}{256}) = 6 +\frac{169}{32} \\ \\ 8(x+\frac{13}{16} )^{2} =\frac{361}{32} \\ \\ (x+\frac{13}{16} )^{2} =\frac{361}{256}\\ \\ (x+\frac{13}{16} ) =(+/-)\sqrt{\frac{361}{256}} \\ \\ (x+\frac{13}{16} ) =(+/-)\frac{19}{16}  \\ \\ x1=-\frac{13}{16} +\frac{19}{16} =\frac{6}{16}\\ \\ x2=-\frac{13}{16} -\frac{19}{16}=-2

the factorization is equal to

8*(x-\frac{6}{16} )*(x+2)=(8x-3)*(x+2)

therefore

<u>the answer is</u>

(8x-3)*(x+2)




3 0
3 years ago
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So only 2 schools will be selected in this regard.

7 0
3 years ago
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