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2 years ago

.guys can you solve anything please

Mathematics

2 answers:

KengaRu [80]2 years ago

6 0

Answer:

3.a)2 $\sqrt[3]{2}$

5.a) x=2

Step-by-step explanation:

vaieri [72.5K]2 years ago

4 0

Answer:

1. If 3^x = 1 then x =0

Step-by-step explanation:

3^0 = 1

3. 2, 9 3, 7, 5, the median is 5

4.3,5,3,4,3 the mode is 3

5. A cube whose volume is 8^3 =(512cm^3)

3. B

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Set A of six numbers has a standard deviation of 3 and set B of four numbers has a standard deviation of 5. Both sets of numbers

Alenkinab [10]

Given:

$\sigma_A=3$

$n_A=6$

$\sigma_B=5$

$n_B=4$

$\overline{x}_A=\overline{x}_B$

To find:

The variance. of combined set.

Solution:

Formula for variance is

$\sigma^2=\dfrac{\sum (x_i-\overline{x})^2}{n}$ ...(i)

Using (i), we get

$\sigma_A^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{n_A}$

$(3)^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}$

$9=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}$

$54=\sum (x_i-\overline{x}_A)^2$

Similarly,

$\sigma_B^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{n_B}$

$(5)^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}$

$25=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}$

$100=\sum (x_i-\overline{x}_B)^2$

Now, after combining both sets, we get

$\sigma^2=\dfrac{\sum (x_i-\overline{x}_A)^2+\sum (x_i-\overline{x}_B)^2}{n_A+n_B}$

$\sigma^2=\dfrac{54+100}{6+4}$

$\sigma^2=\dfrac{154}{10}$

$\sigma^2=15.4$

Therefore, the variance of combined set is 15.4.

7 0

3 years ago

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8090 [49]

Answer:

d= 99 e= 81 f= 99

Step-by-step explanation:

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maks197457 [2]

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3 years ago

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.guys can you solve anything please ​

.guys can you solve anything please