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3 years ago

Please help me with this:)

Mathematics

1 answer:

LenKa [72]3 years ago

8 0

I'm not 100% sure but I think it's the last two choices

sorry if its wrong

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nalin [4]

no clue, man. sorry. i really wish i understood it so i could help you

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3 years ago

What is the x in 4x+20?

Galina-37 [17]

Answer:

the answer is 5 because if you divide it its your answer

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3 years ago

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What is 1/4 times 2 -9

krek1111 [17]

Answer:

-8.5

Step-by-step explanation:

1/4 times 2= 0.5

0.5-9=-8.5

Hope this helps :D

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4 years ago

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8. Write an equation for the relationship school raffle

Otrada [13]

Mia and Jake bought 2 tickets for themselves, how much money did they have to pay?

Hope this helps love <3

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3 years ago

Sketch the region enclosed by y=3x and y=x^2 . Then find the area of the region.

kolezko [41]

Answer:

$A=4.5u^2$

Step-by-step explanation:

The integral of a function gives you the area under the curve, the subtraction of one of the areas from the other will give you the area in between.

The limits of integration are the points where the curves intersect each other(take the curves has a system of equation and solve for x and y):

$y=3x, y=x^2\\3x=x^2\\x^2-3x=0\\x(x-3)=0\\x_1=0\\x-3=0\\x_2=3$

$y_1=3x_1=3(0)=0\\y_2=3x_2=3(3)=9$

The integral will be the subtraction of the curve $y=3x$ and $y=x^2$ (In the graph you can see y=3x is the upper curve):

$\int\limits^3_0 {3x-x^2} \, dx =\left\frac{3x^2}{2}-\frac{x^3}{3}\right|^3_0=\frac{3(3)^2}{2}-\frac{(3)^3}{3}-\left(\frac{3(0)^2}{2}-\frac{(0)^3}{3}\right)\\\int\limits^3_0 {3x-x^2} \, dx =\frac{27}{2}-\frac{27}{3} =13.5-9=4.5u^2$

6 0

3 years ago