All categories

2 years ago

Determine the period of each function. Show Work plzzz

Mathematics

1 answer:

suter [353]2 years ago

7 0

For determining the period of a function, you pick two recognizable tops of the graph and calculate the time difference between them. In this situation the period is 5-1=4, by picking the first two tops

You might be interested in

PLEASE HELPPPPP. URGEENNTT!!! I DONT KNOW HOW TO SOLVE THIS

Oksi-84 [34.3K]

Answer:

A = 58.7 degrees

B = 66.9 degrees

C = 34.1 degrees

Step-by-step explanation:

For <A:

Tan A = $\frac{opposite}{adjacent}$

Tan A = $\frac{23}{14}$

Tan A = 1.6

A = $Tan^{-1} 1.6$

A = 58.7 degrees

For <B:

Sin B = $\frac{opposite}{hypotenuse}$

Sin B = $\frac{23}{25}$

Sin B = 0.92

B = $Sin^{-1} 0.92$

B = 66.9 degrees

For <C:

Sin C = $\frac{opposite}{hypotenuse}$

Sin C = $\frac{14}{25}$

Sin C = 0.56

C = $Sin^{-1}0.56$

C = 34.1 degrees

6 0

3 years ago

Nicholas buys 3/8 pounds of cheese he puts the same amount of cheese on three sandwiches how much cheese does Nicholas put on ea

Lunna [17]

Divide the 3/8 by three. which would be 1/8

5 0

3 years ago

Pleaseeeee help!!! 50 points and BRAINLIEST

pochemuha

Answer:

disagree

Step-by-step explanation:

The interquartile range is a measure of how spread out values are in a data set.

It doesn't actually consider the values, it is found by finding the range between the Q1 / 25th percentile and the Q3 / 75th percentile --and a "range" is found by finding the difference between these two numbers (by subtracting).

So, the weather could have been something like:

79 79 79 80 81 81 83 85 96 97

79 79 79 80 81 | 81 83 85 96 97

meaning that the interquartile range is 6, but these temperatures are not low

(if you want me to explain how to find the interquartile range more thoroughly, please let me know)

6 0

2 years ago

The waiter places a bowl of soup in front of Igor. In a counterclockwise direction, he passes the soup to Elan who then passes i

baherus [9]

$\alpha=\frac{360^o}{12}=30^o\\\\Igor-Elan\to4\cdot30^o=120^o\\\\Elan-Abbey\to4\cdot30^o=120^o\\\\Answer:C$

7 0

4 years ago

For what value of w is4w = 2w - 8

Talja [164]

Answer:

w =-4

Step-by-step explanation:

4w = 2w - 8

Subtract 2w from each side

4w-2w = 2w-2w - 8

2w = -8

Divide by 2

2w/2 = -8/2

w = -4

5 0

3 years ago