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GaryK [48]
4 years ago
13

Solve: x − 2 3 = 61 3 A) 42 9 B) 52 3 C) 6 D) 7

Mathematics
1 answer:
Zepler [3.9K]4 years ago
8 0

Answer:

<h2>D) 7</h2>

Step-by-step explanation:

x-\dfrac{2}{3}=6\dfrac{1}{3}\qquad\text{add}\ \dfrac{2}{3}\ \text{to both sides}\\\\x-\dfrac{2}{3}+\dfrac{2}{3}=6\dfrac{1}{3}+\dfrac{2}{3}\\\\x=6\dfrac{1+2}{3}\\\\x=6\dfrac{3}{3}\\\\x=7

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0.125&lt;1/8 is it comparison
vova2212 [387]

Answer:

yes it is a comparison (but it's incorrect)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Write the equation of the parabola that has the vertex at point (2,7) and passes through the point (−1,3).
mariarad [96]
Step One
Use the vertex to determine the basic equation for the parabola.

y = a(x - 2)^2 + 7 Notice the sign change for x. I have provided a graph to show how this would look with a = 1 (in red.)

What it means is the  2 has to be minus in order that the vertex will shift 2 units in the x direction.

Step Two
Use the point to solve for a.
y = a(x - 2)^2 + 7
When x = - 1
Then y = 3

3 = a(-1 - 2)^2 + 7                combine -1 with - 2
3 = a (-3)^2 + 7
3 = 9a + 7                            Subtract 7 from both sides
3 - 7 = 9a
-4 = 9a                                 Divide by 9.
a = -4/9 
or                                
a = - 0.4444

y = -0.4444(x + 2)^2 + 7 <<<<< answer
y = - 4/9 (x + 2)^2 + 7

Note: if you have choices, list them please.

Note: The red graph is y = (x - 2)^2 + 7 ; a = 1
The blue graph is y = - 4/9(x - 2)^2 + 7 ; a = - 0.44444

You should notice that the a does 3 things to the graph. Before you read the answer, what are those three things? The answer is in the comments.

8 0
4 years ago
Question 4<br> Find x<br> 32°
Tcecarenko [31]

Answer:

picture?

Step-by-step explanation:

5 0
4 years ago
Sum and difference tan(135+30)
Mumz [18]
\tan(x+y)=\dfrac{\sin(x+y)}{\cos(x+y)}=\dfrac{\sin x\cos y+\sin y\cos x}{\cos x\cos y-\sin x\sin y}=\dfrac{\tan x+\tan y}{1-\tan x\tan y}

So,

\tan(135^\circ+30^\circ)=\dfrac{\tan135^\circ+\tan30^\circ}{1-\tan135^\circ\tan30^\circ}

You should know that \tan135^\circ=-1 and \tan30^\circ=\dfrac1{\sqrt3}

Putting everything together,

\tan(135^\circ+30^\circ)=\dfrac{-1+\dfrac1{\sqrt3}}{1-(-1)\left(\dfrac1{\sqrt3}\right)}=\dfrac{1-\sqrt3}{\sqrt3+1}=\sqrt3-2
7 0
4 years ago
Which sum will be neither positive nor negative?<br> 07+(-6)<br> 0 3+2<br> 0-6 + 6<br> 0-4-(-4)
makkiz [27]

Step-by-step explanation:

The awnser is -6+6 because it would end up being 0, which is not positive nor negative

4 0
3 years ago
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