Guys I’m having trouble pls heop
2 answers:
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Based on the above, the Triangle XYZ and ACB are known to be similar triangles since tanX = tanA = 5 over 2 and 5 tenths;
Hence:
- AC = 2 x XY
- CB = 2 x YZ
From the question given; Triangle XYZ is known to have been dilated by a scale factor of 2 to form a type of triangle known as triangle ACB, So therefore, XYZ and ACB are known to be the same or similar triangles.
Since Angles Y and C are known to both measure 90 degrees, and angles A and X are said to be congruent. Therefore:
tanX = tanA = 5 over 2 and 5 tenths
AC = 2 x XY
CB = 2 x YZ
For part B:
cosX=Base/Hypotenuse
cos A=AC/AB
AC = 2.05
AB = 5.59
Therefore, Based on the above, the Triangle XYZ and ACB are known to be similar triangles since tanX = tanA = 5 over 2 and 5 tenths;
Hence:
- AC = 2 x XY
- CB = 2 x YZ
Learn more about triangles from
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Answer: Option D
Step-by-step explanation:
Note that the projectile height as a function of time is given by the quadratic equation
To find the maximum height of the projectile we must find the maximum value of the quadratic function.
By definition the maximum value of a quadratic equation of the form
is located on the vertex of the parabola:
Where
In this case the equation is:
Then
So: