Hi, there!
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4 times a number "q" = 4q
"Plus 25" +25
Putting these two parts together
![\sf{4q+25}](https://tex.z-dn.net/?f=%5Csf%7B4q%2B25%7D)
Now, we can't evaluate this expression (like we're asked) unless we know what q is. And it happened that we <em>are</em> given what q is, it's 2. So, we can substitute its value into the expression:
![\sf{4(2)+25}](https://tex.z-dn.net/?f=%5Csf%7B4%282%29%2B25%7D)
![\sf{8+25}](https://tex.z-dn.net/?f=%5Csf%7B8%2B25%7D)
![\sf{33}](https://tex.z-dn.net/?f=%5Csf%7B33%7D)
Hope the answer - and explanation - made sense.
happy studying!!
Answer:
I'll try to find the answer 4 u I'ma solve it rq
Parallel lines have the same gradient
rearrange the equation so they will be in the form y = mx + c, where m is the gradient
y = -6x - 8
y = 2x + 5
as you can see, since they do not have the same gradient, they are not parallel lines
Answer:
1 perpendicular
Step-by-step explanation:
it's the only way for them to be equal