Let's say the first number is "a"
the next consecutive can just be "a+1" and the next, you guessed it, "a+2"
the two smaller ones are a and a+1, the larger one is a+2
now, the product of "a" and "a+1" equals 5 times "a+2" but less by 5
thus a(a + 1) = 5(a + 2) - 5 <----- solve for "a"
Answer:
a + b = 5.30
a + b = 7
No
Step-by-step explanation:
Expressing the information as system of linear equation :
Let apples = a, oranges = b
If $5.30 is charged for one apple and one orange, then we have ;
a + b = 5.30 - - - (1)
If $14 is charged for 2 apples and 2 oranges, then we have ;
2a + 2b = 14 - - - - (2)
a + b = 7
Since both equations gives varying combined cost for equal amount of the fruit, then a unique cost cannot be obtained for each fruit from the systems of equation using simultaneous equation process.
From (1)
a = 5.30 - b
Put a = 5.30 - b in (2)
2(5.30 - b) + 2b = 14
10.6 - 2b + 2b = 14
10.6 = 14 - - - - - (variables cancels out).
Sn = a1 * (1 - r^n)
----------
1 - r
n = 5 so answer =
1 * (1 - (1/2)^5
--------------- = 31/16
1 - 1/2
The answer is y=-9
negative 9 remember that
Move the constant to the right-hand side and change its sign and calculate
