Answer:
The length of the base is 11 meters.
Step-by-step explanation:
The diagram of the triangle is not shown; However, the given details are enough to solve this question.
Given
<em>Shape: Triangle</em>
<em>Represent the height with h and the base with b</em>


Required
Find the length of the base
The area of a triangle is calculated as thus;

Substitute 22 for Area and 3 + 2h for b
The formula becomes

Multiply both sides by 2


Open the bracket


Subtract 44 from both sides


Rearrange


At this point, we have a quadratic equation; which is solved as follows:




Split the above


Solve the above linear equations separately

Add 4 to both sides


---- <em>First value of h</em>

Subtract 11 from both sides



Divide both sides by 2

<em> ------ Second value of h</em>
Since height can be negative, we'll discard 
Hence, the usable value of height is 
Recall that 
Substitute 4 for h



Hence, the length of the base is 11 meters