The answer I got was 12 if needed I can take a picture of how I worked it
Answer:
<em>Choice: B.</em>
Step-by-step explanation:
<u>Operations With Functions</u>
Given the functions:
![f(x)=\sqrt[3]{12x+1}+4](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7B12x%2B1%7D%2B4)
The function (g-f)(x) can be obtained by replacing both functions and subtracting them as follows:
![(g-f)(x)= \log(x-3)+6 - (\sqrt[3]{12x+1}+4)](https://tex.z-dn.net/?f=%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%2B6%20-%20%28%5Csqrt%5B3%5D%7B12x%2B1%7D%2B4%29)
Operating:
![(g-f)(x)= \log(x-3)+6 - \sqrt[3]{12x+1}-4](https://tex.z-dn.net/?f=%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%2B6%20-%20%5Csqrt%5B3%5D%7B12x%2B1%7D-4)
Joining like terms:
![\boxed{(g-f)(x)= \log(x-3) - \sqrt[3]{12x+1}+2}](https://tex.z-dn.net/?f=%5Cboxed%7B%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%20-%20%5Csqrt%5B3%5D%7B12x%2B1%7D%2B2%7D)
Choice: B.
<h2><u><em>
If you rather have the link to get this info lmk!!</em></u></h2>
Example: f(x) = 2x+3 and g(x) = x2
"x" is just a placeholder. To avoid confusion let's just call it "input":
f(input) = 2(input)+3
g(input) = (input)2
Let's start:
(g º f)(x) = g(f(x))
First we apply f, then apply g to that result:
Function Composition
- (g º f)(x) = (2x+3)2
What if we reverse the order of f and g?
(f º g)(x) = f(g(x))
First we apply g, then apply f to that result:
Function Composition
- (f º g)(x) = 2x2+3
We get a different result! When we reverse the order the result is rarely the same. So be careful which function comes first.
<h2 />
Your answer is 4/14 or 2/7. There are two possibilities when you flip a coin, heads or tails. Then for the spinner there are 7. Multiply them by each other to get the total number of outcomes of the situation of 14. Then there are only 4 odd numbers from 1-7. This means that you would only be able to get an odd number and heads 4 times.
Hope this helped!
Quotient means divide
95/x <== ur expression
