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choli [55]
2 years ago
5

If they bake only cakes, then in a single day George can bake 10 cakes while Greta can bake 5 cakes. If they only make pies, the

n in a single day George can bake 10 pies while Greta can bake 4 pies. We then know that:
Mathematics
1 answer:
NikAS [45]2 years ago
8 0

Answer:

George rate of baking cakes is ten cakes per day and it is double of Greta rate of baking cake.

George rate of baking pies is ten pies per day and it is two and a half times of Greta's rate of baking pies. There ratio for baking cakes is 1:2 for Greta and George respectively and for baking pies is 1:2.5 for Greta and George respectively

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9 divided by 622 long division
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6 0
3 years ago
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Which of the following best forms the figure shown
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Where is the picture? If you could add your picture I’d be glad to help you!! :)
4 0
3 years ago
Draw a number line and show all numbers that are between 1 and 20 and have exactly 4 factors
True [87]
1 = 1 x 1 
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2 = 1 x 2
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3 = 1 x 3
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4 = 1 x 4
4 = 2 x 2
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5 = 1 x 5
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8 = 2 x 4
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9  = 1 x 9
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10 = 1 x 10
10 = 2 x 5
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11 = 1 x 11
2 factors

12 = 1 x 12
12 = 2 x 6
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14 = 1 x 14
14 = 2 x 7
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15 = 1 x 15
15 = 3 x 5
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16 = 1 x 16
16 = 2 x 8
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2 factors

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1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
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8 0
3 years ago
A gun mass of 5 kg fired a bullet of mass 10 g with the velocity of 360 km/h. What
klemol [59]

Answer:

The recoil velocity of the gun is 0.72\,\,\frac{km}{h}  and is pointing in opposite direction to the velocity of the bullet.

Step-by-step explanation:

Use conservation of linear momentum, which states that the momentum of the bullet (product of the bullet's mass times its speed) should equal in absolute value the momentum of the recoiling gun (its mass times its recoil velocity).

We also write the mass of the bullet in the same units as the mass of the gun (for example kilograms). Mass of the bullet = 0.010 kg

In mathematical terms, we have:

5\, kg * v= 0.01 \,kg\,* 360\,\frac{km}{h} \\v=\frac{0.01\,*360}{5} \,\,\frac{km}{h}\\v=0.72\,\,\frac{km}{h}

6 0
3 years ago
A private and a public university are located in the same city. For the private university, 1038 alumni were surveyed and 647 sa
Snezhnost [94]

Answer:

The difference in the sample proportions is not statistically significant at 0.05 significance level.

Step-by-step explanation:

Significance level is missing, it is  α=0.05

Let p(public) be the proportion of alumni of the public university who attended at least one class reunion  

p(private) be the proportion of alumni of the private university who attended at least one class reunion  

Hypotheses are:

H_{0}: p(public) = p(private)

H_{a}: p(public) ≠ p(private)

The formula for the test statistic is given as:

z=\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}} where

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  • p2 is the sample proportion of private university students who attended at least one class reunion  (\frac{647}{1038}=0.623)
  • p is the pool proportion of p1 and p2 (\frac{808+647}{1311+1038}=0.619)
  • n1 is the sample size of the alumni from public university (1311)
  • n2 is the sample size of the students from private university (1038)

Then z=\frac{0.616-0.623}{\sqrt{{0.619*0.381*(\frac{1}{1311} +\frac{1}{1038}) }}} =-0.207

Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.  

6 0
3 years ago
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