Your answer would have to be 69with the remainder of 1
(open the picture for the shown work :) )
Where is the picture? If you could add your picture I’d be glad to help you!! :)
1 = 1 x 1
1 factors
2 = 1 x 2
2 factors
3 = 1 x 3
2 factors
4 = 1 x 4
4 = 2 x 2
3 factors
5 = 1 x 5
2 factors
6 = 1 x 6
6 = 2 x 3
4 factors
7 = 1 x 7
2 factors
8 = 1 x 8
8 = 2 x 4
4 factors
9 = 1 x 9
9 = 3 x 3
3 factors
10 = 1 x 10
10 = 2 x 5
4 factors
11 = 1 x 11
2 factors
12 = 1 x 12
12 = 2 x 6
12 = 3 x 4
6 factors
13 = 1 x 13
2 factors
14 = 1 x 14
14 = 2 x 7
4 factors
15 = 1 x 15
15 = 3 x 5
4 factors
16 = 1 x 16
16 = 2 x 8
16 = 4 x 4
5 factors
17 = 1 x 17
2 factors
18 = 1 x 18
18 = 2 x 9
18 = 3 x 6
6 factors
19 = 1 x 19
2 factors
20 = 1x 20
20 = 2 x10
20 = 4 x 5
6 factors
So they are 6, 8, 10, 14 and 15 on the number line
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
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Answer:
The recoil velocity of the gun is
and is pointing in opposite direction to the velocity of the bullet.
Step-by-step explanation:
Use conservation of linear momentum, which states that the momentum of the bullet (product of the bullet's mass times its speed) should equal in absolute value the momentum of the recoiling gun (its mass times its recoil velocity).
We also write the mass of the bullet in the same units as the mass of the gun (for example kilograms). Mass of the bullet = 0.010 kg
In mathematical terms, we have:

Answer:
The difference in the sample proportions is not statistically significant at 0.05 significance level.
Step-by-step explanation:
Significance level is missing, it is α=0.05
Let p(public) be the proportion of alumni of the public university who attended at least one class reunion
p(private) be the proportion of alumni of the private university who attended at least one class reunion
Hypotheses are:
: p(public) = p(private)
: p(public) ≠ p(private)
The formula for the test statistic is given as:
z=
where
- p1 is the sample proportion of public university students who attended at least one class reunion (
)
- p2 is the sample proportion of private university students who attended at least one class reunion (
)
- p is the pool proportion of p1 and p2 (
)
- n1 is the sample size of the alumni from public university (1311)
- n2 is the sample size of the students from private university (1038)
Then z=
=-0.207
Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.