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Bond [772]
3 years ago
5

PLS ANSWER ASAP Subtract. −13−(−27) Enter your answer in the box.

Mathematics
2 answers:
Verizon [17]3 years ago
8 0

Answer:

14

Step-by-step explanation:

Art [367]3 years ago
7 0

Answer:

14

Step-by-step explanation:

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Find the median. 90, 88, 100, 82, 80.<br> PLEASE
Ludmilka [50]

Answer:

Step-by-step explanation:

80, 82, 88, 90, 100

Now cross out the numbers starting with 80 and 100 and keep going till you get the middle number which would be 88

5 0
3 years ago
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What value of x makes the equation true?<br><br> 16 + (18 + 10) = (x + 18) + 10<br><br> x = ?
choli [55]

Answer:

  See below

Step-by-step explanation:

16 + (18 + 10) = (x + 18) + 10x

16 + 28 = (x + 18) + 10x        Add like terms in the parentheses

44 = (x + 10x) + 18               Use the community property to regroup like

                                            terms

44 = 11x + 18                         Simply

<u>-18 =        -18</u>                         Substract 18 from both side

26  = 11x                               Simply

<u>26</u>  =  <u>11x</u>                              Divide by 11

11        11

2\frac{4}{11} = x                               Reduce                

3 0
2 years ago
9 430 000 000 000 km in standard form
mote1985 [20]
9.43 x 10^12 is the answer
8 0
3 years ago
A hypothetical square grows so that the length of its diagonals are increasing at a rate of 8m/min. How fast is the area of the
ad-work [718]

Answer: The area of the square is increasing at a rate of 90.4 m2/min (square meters/minute)

Step-by-step explanation: Please see the attachments below

7 0
3 years ago
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Using properties of sets show that : a) A ∩ (A’ U B) = A ∩ B b) A ∩ (A U B )’ = Ф
asambeis [7]

Answer:

a) From A ∩ A' = ∅, we have;

A ∩ (A' ∪ B) = A ∩ B

b) From A ∩ (A' ∩ B') = (A ∩ A') ∩ B' and A ∩ A' = ∅, we have;

A ∩ (A ∪ B)' = ∅

Step-by-step explanation:

a) By distributive law of sets, we have;

A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)

From the complementary law of sets, we have;

A ∩ A' = ∅

Therefore, for A ∩ (A' ∪ B) = A ∩ B, we have

A ∩ (A' ∪ B) = (A ∩ A') ∪ (A ∩ B) (distributive law of sets)

A ∩ A' = ∅ (complementary law of sets)

Therefore;

(A ∩ A') ∪ (A ∩ B) = ∅ ∪ (A ∩ B)  = (A ∩ B) (Addition to zero identity property)

∴  A ∩ (A' ∪ B) = A ∩ B

b) By De Morgan's law

(A ∪ B)' = A' ∩ B'

Therefore, A ∩ (A ∪ B)' = A ∩ (A' ∩ B')

By associative law of sets, we have;

A ∩ (A' ∩ B') = (A ∩ A') ∩ B'

A ∩ A' = ∅ (complementary law of sets)

Therefore, (A ∩ A') ∩ B' = ∅  ∩ B' = ∅

Which gives;

A ∩ (A ∪ B)' = ∅.

4 0
3 years ago
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