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LuckyWell [14K]
3 years ago
7

The teacher spent 1/8 of the class period reviewing the answers to a worksheet. The class period was 1 1/2 hours length. How man

y minutes did the teacher spend reviewing the worksheet? Enter your response as a decimal.
Mathematics
1 answer:
Anvisha [2.4K]3 years ago
7 0

11.25 maybe?  ..............

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Write a two column proof 2x+6 and 96 prove: x=45
viktelen [127]
2x+6=96
2(45)+6
90+6=96
96=96
hope this helps u out!
6 0
3 years ago
Find the length of arc AB
Alexeev081 [22]

Answer:

the answer is 4pi or 12.56637061

Step-by-step explanation:

the arc length equals 2pi x radius ( known angle (120) / 360 which equals 4pi or 12.56637061

8 0
3 years ago
Help i did the first part and id.k the rest.....
34kurt

Answer:

w=6x+1.25

Step-by-step explanation:

6 0
3 years ago
Complete parts ​(a) through ​(c) below.
Yuki888 [10]

Answer:

a)t_{crit}= 1.34

b) t_{crit}=-2.539

c) t_{crit}=\pm 2.228

Step-by-step explanation:

Part a

The significance level given is \alpha=0.1 and the degrees of freedom are given by:

df = n-1= 15

Since we are conducting a right tailed test we need to find a critical value on the t distirbution who accumulates 0.1 of the area in the right and we got:

t_{crit}= 1.34

Part b

The significance level given is \alpha=0.01 and the degrees of freedom are given by:

df = n-1= 20-1=19

Since we are conducting a left tailed test we need to find a critical value on the t distirbution who accumulates 0.01 of the area in the left and we got:

t_{crit}=-2.539

Part c

The significance level given is \alpha=0.05 and \alpha/2 =0.025 and the degrees of freedom are given by:

df = n-1= 11-1=10

Since we are conducting a two tailed test we need to find a critical value on the t distirbution who accumulates 0.025 of the area on each tail and we got:

t_{crit}=\pm 2.228

4 0
3 years ago
Justin's car used 12 gallons to travel 252 miles. At what rate does the car use gas, in
s2008m [1.1K]

Answer:

All you have to do is divide the miles by the gallons... 252 miles ÷ 12 gallons = 21 miles/gallons

Your final answer is 21 miles/gallon!!

7 0
3 years ago
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