9514 1404 393
Answer:
5 1/16 ft
Step-by-step explanation:
h(t) = -16t(t -18/16) . . . . put in intercept form
The function describes a parabola that opens downward. It has zeros at t=0 and t=9/8. The maximum height will be found at the vertex of the parabola, halfway between these zeros.
f(9/16) = (-16)(9/16)² +18(9/16) = 81/16 = 5 1/16 . . . . feet
The approximate maximum height of the leopard is 5 1/16 feet.
Not sure if I'm right but I think it's 3(x - 6) (x^2 + 5x)
Step-by-step explanation:
3x^3 - 3x^2 - 90x
Apply GCF: 3 (x^3 - x^2 - 30)
Split 30 into -6 and 5
(x^3 - 6x^2) (5x^2 - 30x)
GCF of both: x^2 (x - 6) and 5x (x - 6)
DON'T FORGET TO CARRY THE 3
And your answer is 3 (x - 6) (x^2 + 5x)
Multiply negative 0.5 times negative 8
The answer is 4