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Gemiola [76]
3 years ago
14

What is the arc length when theta= 2pi/5 and the radius is 6 cm?

Mathematics
1 answer:
Ahat [919]3 years ago
4 0

\bf \textit{arc's length}\\\\ s=r\theta ~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad radians\\ \cline{1-1} r=6\\ \theta =\frac{2\pi }{5} \end{cases}\implies s=6\cdot \cfrac{2\pi }{5}\implies s=\cfrac{12\pi }{5}\implies s\approx 7.54

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Based on the net shown below, what is the surface area of the pyramid to the nearest square inch. please show work
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Pyramid Surface Area = (½ * Perimeter of Base * Slant Height) + Base Area

Perimeter of Base = 6 * 4 = 24
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Pyramid Surface Area = (½ * Perimeter of Base * Slant Height) + Base Area
Pyramid Surface Area = (½ * 24 * 6) + 36
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3 0
3 years ago
PLEASE HELP VERY URGENT
worty [1.4K]

Answer:

A. square root of a^2 + b^2 for both answers

Step-by-step explanation:

The first problem, we are given

a^2 + b^2 = c^2

What we do is solve for c.

sqrt(a^2 + b^2) = c

c = sqrt(a^2 + b^2)

For problem 2,

WE can apply the Pythagorean theorem because we have a right triangle.

The equations is

a^2 + b^2 = c^2 like the first problem

Solving gets us

sqrt(a^2 + b^2) = c

c = sqrt(a^2 + b^2)

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4 years ago
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Step-by-step explanation:

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Solution:

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