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2 years ago

May I please receive help?

Mathematics

2 answers:

BARSIC [14]2 years ago

6 0

Answer: m∠2 = 28°

Step-by-step explanation: Right bro. 1000%

Slav-nsk [51]2 years ago

5 0

You set the problem up: 3x + x = 84. With x representing angle 2. 4x=84 makes x = 21. Therefore angle 2 is 21.

You might be interested in

(a) Use differentiation to find a power series representation for

choli [55]

Answer:1/(3+x)=(1/3)

(1−(−x/3))

1/(3+x)=(1/3)1(1−(−x/3))

Use this fact that

1/(1−t)=

∑

∞

(∗)

1/(1−t)=∑0∞tn (∗)

where

|t|<1

. I mean take

t=−x/3

and...

Note that

|−t|=|t|<1

is the radius of convergence

Step-by-step explanation:

8 0

3 years ago

Find the length of the following two-dimensional curve. r (t ) = (1/2 t^2, 1/3(2t+1)^3/2) for 0 < t < 16

andrezito [222]

Answer:

r = 144 units

Step-by-step explanation:

The given curve corresponds to a parametric function in which the Cartesian coordinates are written in terms of a parameter "t". In that sense, any change in x can also change in y owing to this direct relationship with "t". To find the length of the curve is useful the following expression;

$r(t)=\int\limits^a_b ({r`)^2 \, dt =\int\limits^b_a \sqrt{((\frac{dx}{dt} )^2 +\frac{dy}{dt} )^2)} dt$

In agreement with the given data from the exercise, the length of the curve is found in between two points, namely 0 < t < 16. In that case a=0 and b=16. The concept of the integral involves the sum of different areas at between the interval points, although this technique is powerful, it would be more convenient to use the integral notation written above.

Substituting the terms of the equation and the derivative of r´, as follows,

$r(t)= \int\limits^b_a \sqrt{((\frac{d((1/2)t^2)}{dt} )^2 +\frac{d((1/3)(2t+1)^{3/2})}{dt} )^2)} dt$

Doing the operations inside of the brackets the derivatives are:

1 ) $(\frac{d((1/2)t^2)}{dt} )^2= t^2$

2) $\frac{(d(1/3)(2t+1)^{3/2})}{dt} )^2=2t+1$

Entering these values of the integral is

$r(t)= \int\limits^{16}_{0} \sqrt{t^2 +2t+1} dt$

It is possible to factorize the quadratic function and the integral can reduced as,

$r(t)= \int\limits^{16}_{0} (t+1) dt= \frac{t^2}{2} + t$

Thus, evaluate from 0 to 16

$\frac{16^2}{2} + 16$

The value is $r= 144 units$

5 0

3 years ago

Can anyone please help anyone bro

xxTIMURxx [149]

F(x) and g(x) were inverse functions, then if f(a) = b, then g(b) = a

f(x) = (5x+1) / x g(x) = x / (5x+1)

f(1) = 6, but g(6) = 6/31 ≠ 1

So, f(x) and g(x) are NOT inverse functions.

5 0

2 years ago

48 = 3/2y <br> simplify your answer as much as possible

Sloan [31]

$48 = 1\frac{1}{2}y \\48(\frac{2}{3}) = 1\frac{1}{2}y(\frac{2}{3}) \\32 = y$

4 0

3 years ago

if you could respond with the work shown that would be amazing! i rate people very nicely!! this is due before 7 AM EST time :)

yulyashka [42]

Answer:

35ft squared

Step-by-step explanation:

First lets try solving the rectangular middle part

Width is 3 ft

Height is 5ft + 4ft = 9ft

3*9ft= 27ft. This is area of middle rectangular section

For the triangle, we subtract 3 from the rectangle from 11ft and divide by 2 because the two triangle on the edges are the same.

11-3=8

8/2=4

Triangle area formula = Base*Height / 2

4*4/2

16/2

4ft squared

and the other triangles area is also 4ft squared because they are congruent. So you add all the sections of the area up

27ft+4ft+4ft=35ft squared

35ft squared is the answer.

Hope this helps :)

4 0

3 years ago