A particle moves along the curve y = 4x2 + 1 in such a way that the x value is increasing at the rate of 2 units per second. At
what rate is y changing when x = 1?.
1 answer:
By differentiating both sides of y = 4x² + 1 with respect to time t, we have
dy/dt = 8x dx/dt
If the x value changes at a rate of +2 units/second (that is, dx/dt = 2) at the moment x = 1, then the y value changes at a rate of
dy/dt = 8 • 1 • 2 units/s = 16 units/s
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