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3 years ago

7

What are the attributes of fractions that are equivalent to 100%

1 answer:

Svetach [21]3 years ago

7 0

Well, think of a fraction. The numerator is telling what how many you have and the denominator is the total amount available. A fraction can be written as a/b, or whatever how much value a you have out of the total amount you can have. So if you have 3 apples out of the available 3 apples, you have 100% of the apples. So the attritibutes are a/b when a and b are the same value, and when dividing fractions, when you divide by the reciprocal.

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Find the measure of ∠FEG.<br> A) 25° <br> B) 65° <br> C) 80° <br> D) 90°

MissTica

First, you have to set 5x equal to (3x+10). They are vertical angles and therefore congruent.

5x = 3x+10 The variable should only be on one side of the equation,

5x - 3x = 10 Therefore subtract 3x from both sides

2x = 10 Divide by 2 on both sides.

x = 5

We're not done yet, since we've found the x-value we have to solve for ∠GEC.

∠GEC = 3x+10 = 3(5)+10 = 15+10 = 25°

∠GEC and ∠FEG form a right angle. This means that the sum of the two angles is 90°

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65° = x

<h2>∠FEG = 65° The Answer is B</h2>

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3 years ago

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El recorrido de una etapa de una vuelta ciclística tiene una longitud de 213 kilometros y un ciclista recorre 2/3 del trayecto e

Maurinko [17]

the question in English

The route of a stage of a cycle tour is 213 km long and a cyclist covers 2/3 of the route in five hours.

a) How many kilometers are left to finish the stage?

b) If he continues with the same average speed, how much time does he have left to finish the stage?

Step 1

we know that

1) Total kilometers of a stage is $213\ km$

2) The cyclist covers $\frac{2}{3}$ of the route

so

the kilometers remaining to finish the stage is equal to

$(1-\frac{2}{3})*213= \frac{1}{3}*213\\ \\=71\ km$

therefore

<u>the answer Part a) is </u>

$71\ km$

Step 2

<u>Find the average speed of the cyclist</u>

we know that

the speed is equal to

$speed=\frac{distance}{time}$

we have

$time=5\ hours\\ distance=\frac{2}{3}*213=142\ km$

substitute

$speed=\frac{142}{5}=28.4\frac{km}{h}$

Step 3

<u>Find the time remaining to finish the stage</u>

we know that

$speed=\frac{distance}{time}$

Solve for the time

$time=\frac{distance}{speed}$

we have

$distance=71\ km\\ speed=28.4\frac{km}{h}$

substitute

$time=\frac{71}{28.4}=2.5\ hours$

therefore

<u>the answer Part b) is</u>

$2.5\ hours$

8 0

3 years ago