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3 years ago

Create two groups of cards with the SAME SUM using as many cards as possible using the numbers 8 7 6 2 1 3.

Mathematics

1 answer:

laila [671]3 years ago

7 0

Answer:

Explained below.

Step-by-step explanation:

In this case we need to form two group of cards (consisting of any number of cards) having the same sum using the cards numbered as 8, 7, 6, 2, 1, 3.

The possible groups are as follows:

Group 1 Group 2 Sum

{8, 1} {7, 2} 9

{8, 2} {7, 3} 10

{8, 3} {7, 3, 1} 11

{8, 1, 3} {7, 3, 2} 12

{8, 2, 3} {7, 2, 1, 3} 13

{8, 3, 2, 1} {7, 6, 1} 14

And so on.

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-3n+4

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3 years ago

The perimeter of a triangle is 38cm. The first side is 10cm longer than the second side, the third side is twice as long as the

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8 0

3 years ago

Ariela is selling tickets to a play. adult tickets cost $12.25 and children's tickets cost $8.75. the total amount of money she

Romashka [77]

12.25x + 8.75y > = 90 (thats greater then or equal) <== ur inequality

4 0

3 years ago

Read 2 more answers

Solve the equation 8y-6=5y+12

Bumek [7]

8y - 6 = 5y + 12
- 5y    - 5y
3y - 6 = 12
      + 6   + 6
   3y = 18
      3     3
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5 0

3 years ago

1. Carter will install fencing all around the flat area of his

MariettaO [177]

Answer:

Amount of fencing required = 75 yards

Step-by-step explanation:

Distance between the two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by the formula,

d = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance between A(3, 6) and B(3, -2) = $\sqrt{(3-3)^2+(6+2)^2}$

= 8 yards

Distance between B(3, -2) and C(-7, 4) = $\sqrt{(3+7)^2+(-2-4)^2}$

= $\sqrt{136}$

= 11.66 ≈ 12 yards

Distance between C(-7, 4) and D(-7, -2) = $\sqrt{(-7+7)^2+(4+2)^2}$

= 6 yards

Distance between D(-7, -2) and E(-3, -2) = $\sqrt{(-7+3)^2+(-2+2)^2}$

= 4 yards

Distance between E(-3, -2) and F(-3, -8) = $\sqrt{(-3+3)^2+(-2+8)^2}$

= 6 yards

Distance between F(-3, -8) and G(3, -8) = $\sqrt{(-3-3)^2+(-8+8)^2}$

= 6 yards

Distance between G(3, -8) and H(10, -12) = $\sqrt{(3-10)^2+(-8+12)^2}$

= $\sqrt{49+16}$

= $\sqrt{65}$

= 8.06 ≈ 8 yards

Distance between H(10, -12) and J(10, 6) = $\sqrt{(10-10)^2+(-12-6)^2}$

= 18 yards

Distance between A(3, 6) and J(10, 6) = $\sqrt{(10-3)^2+(6-6)^2}$

= 7 yards

Since length of fence required = perimeter of the flat area

Perimeter of the given area = 8 + 12 + 6 + 4 + 6 + 6 + 8 + 18 + 7

= 75 yards

Therefore, amount of fencing required = 75 yards

8 0

3 years ago

Create two groups of cards with the SAME SUM using as many cards as possible using the numbers 8 7 6 2 1 3.​

Create two groups of cards with the SAME SUM using as many cards as possible using the numbers 8 7 6 2 1 3.