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SVEN [57.7K]
3 years ago
13

Write a program that outputs the number of characters, words, and lines in the files that are supplied as command-line arguments

.
Computers and Technology
1 answer:
Dahasolnce [82]3 years ago
4 0
Public class Exercise_13 {

public static void main(String[] args) {

if (args.length != 1) {
System.out.println("Invalid arguments.");
System.out.println("Usage: java Chapter_12.Exercise_13 filename");
System.exit(1);
}
File filename = new File(args[0]);
if (!filename.exists()) {
System.out.println(filename + " does not exist.");
System.exit(2);
}

int characters = 0;
int words = 0;
int lines = 0;

try {
Scanner input = new Scanner(filename);
while (input.hasNext()) {
String s = input.nextLine();
lines++;
characters += s.length();
String[] split = s.split(" ");
for (String word : split) {
words++;
}
}

} catch (FileNotFoundException ex) {
ex.printStackTrace();
}

System.out.println("Characters: " + characters);
System.out.println("Words: " + words);
System.out.println("Lines: " + lines);


}
}
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Write a C++ program to find all numbersless than 1000 which are:
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Answer:

The c++ program is shown below.

#include <iostream>

using namespace std;

int main() {    

   cout<<"Numbers less than 1000 which are divisible by 7"<<endl;    

   for(int k=1; k<1000; k++)

   {

       // number should give remainder 0 which show complete divisibility

       if(k%7 == 0)

           cout<<k<<"\t";

   }    

   cout<<endl<<"Numbers less than 1000 which are divisible by 11"<<endl;    

   for(int k=1; k<1000; k++)

   {

       if(k%11 == 0)

           cout<<k<<"\t";

   }    

   cout<<endl<<"Numbers less than 1000 which are divisible by 7 but not divisible by 11"<<endl;    

   for(int k=1; k<1000; k++)

   {

       // for 11, number should not give remainder 0 which shows incomplete divisibility

       if(k%7 == 0 && k%11 != 0)

           cout<<k<<"\t";

   }    

   cout<<endl<<"Numbers less than 1000 which are divisible by 7 and divisible by 11"<<endl;

   

   for(int k=1; k<1000; k++)

   {

       if(k%7 == 0 && k%11 == 0)

           cout<<k<<"\t";

   }    

   cout<<endl<<"Numbers less than 1000 which are not divisible by 7 and not divisible by 11"<<endl;    

   for(int k=1; k<1000; k++)

   {

       if(k%7 != 0 && k%11 != 0)

           cout<<k<<"\t";

   }    

   return 0;

}

Explanation:

The test for divisibility is done by using the modulus operator which is used as a condition inside the if statement. This test is done inside for loop.

All the numbers from 1 to 999, less than 1000, are divided by 7 and/ or 11 depending on the sub question. Only the numbers which are completely divisible are displayed. Divisible numbers give remainder 0 always.

The divisibility test by 7 is shown below.

cout<<"Numbers less than 1000 divisible by 7"<<endl;    

   for(int k=1; k<1000; k++)

   {

       if(k%7 == 0)

           cout<<k<<"\t";

   }    

In other words, all the numbers divisible by 7 are same as the numbers in the table of 7.

The same logic shown above is applied for other sub questions to test for divisibility by 11 and combination of 7 and 11.

To improve readability, tabs and new lines are inserted at appropriate places.

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Explanation:

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