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alisha [4.7K]
2 years ago
13

Kayla measured the distances surrounding a lake, as

Mathematics
1 answer:
Monica [59]2 years ago
3 0

Considering ΔADE and ΔACB as similar triangles, the distance across the lake is, <em>DE = 107.1 ft</em>.

<h3>Similar Triangles</h3>
  • Similar triangles are formed if a line segment that is parallel to a one of the sides of a triangle joins the two other sides of the triangle.
  • For triangles that are similar to each other, the ratio of their corresponding sizes are congruent.

The image shows two similar triangles, ΔADE and ΔACB. Therefore:

AD/AC = DE/CB

  • Substitute

75/(75 + 100) = DE/250

75/175 = DE/250

DE = 107.1 ft

Therefore, considering ΔADE and ΔACB as similar triangles, the distance across the lake is, <em>DE = 107.1 ft</em>.

Learn more about similar triangles on:

brainly.com/question/2644832

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man you got this

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