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pickupchik [31]
3 years ago
13

Select the best answer for the question

Mathematics
1 answer:
artcher [175]3 years ago
3 0

Answer:

C

HOWEVER: "Less Than" is usually depicted as a dashed line at the border. and there MUST be an OR between these two equations to include all of the blue area. An "and" there would exclude the area between the edge lines.

Step-by-step explanation:

2x + y < 10

       y < -2x + 10

3x + 2y < 12

       2y < -3x + 12

         y < -1.5x + 6

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Please can someone help? As i'm not confident this is right for factorising 4b^2 + 8b + 3 ​
SIZIF [17.4K]

Answer:

your answer is correct

Step-by-step explanation:

4b² + 8b + 3

Consider the factors of the product of the coefficient of the b² term and the constant term which sum to give the coefficient of the b- term.

product = 4 × 3 = 12 and sum = + 8

The factors are 2 and 6

Use these factors to split the b- term

4b² + 2b + 6b + 3 ( factor the first/second and third/fourth terms )

= 2b(2b + 1) + 3(2b + 1) ← factor out (2b + 1) from each term

= (2b + 1)(2b + 3)

5 0
3 years ago
What is the solution set of the following equation? 4\5^2= 2x- 4\5
Elden [556K]

Answer:

x = 18/25

Step-by-step explanation:

(4/5)² = 2x - 4/5

16/25 = 2x - 4/5

16/25 = 2x - 20/25

36/25 = 2x

x = 18/25

3 0
3 years ago
Read 2 more answers
If addenda are 170 and 130 what is the sum
Juliette [100K]
The answer is 200 of 170
4 0
3 years ago
Which lists all of the shapes that are in a two-dimensional net of a square pyramid? 6 squares 4 triangles 1 square and 3 triang
MakcuM [25]

Answer:

4 triangles and 1 square

Step-by-step explanation:

Required

The shapes in two-dimensional net of a square pyramid

To do this, I will attach an attachment of a 2D net of a square pyramid (see attachment)

From the attachment, we can see that:

The 2d shape of the pyramid is made of 4 triangles and 1 square

7 0
3 years ago
Find the coordinates of the vertices of polygon H´J´K´L´ after polygon HJKL is dilated using the given scale factor. H(–1, –6),
alex41 [277]

Answer:

  • H'  (-3, -18)
  • J'  (3, -9)
  • K (-15, -3)
  • L = (15, -15)

Step-by-step explanation:

Given:

H(–1, –6), J(1, –3), K(–5, –1), and L(5, –5)

We know that polygons are HJKL relaxes using the scale factor 3. This means that, to find the coordinates of the vertices of the polygon H'J'K'L ', we need to multiply the coordinate system x and y coordinates of each vertex by a factor of 3  proportion as following:

  • H' = (-1*3, -6*3) = (-3, -18)
  • J' = (1*3 , -3*3) = (3, -9)
  • K = (-5*3, -1*3) =(-15, -3)
  • L = (5*3, -5*3) = (15, -15)

8 0
3 years ago
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