Use y=mx+b , it will will help u!
By applying Pythagorean theorem, we have proven that the point (-1/2, -√3/2) lies on the unit circle.
<h3>How to prove this point lies on the unit circle?</h3>
In Trigonometry, an angle with a magnitude of -120° is found in the third quarter and as such, both x and y would be negative. Also, we would calculate the reference angle for θ in third quarter as follows:
Reference angle = 180 - θ
Reference angle = 180 - 120
Reference angle = 60°.
For the coordinates, we have:
sin(-120) = -sin(60) = -1/2.
cos(-120) = -cos(60) = -√3/2.
By applying Pythagorean theorem, we have:
z² = x² + y²
z = √((-1/2)² + (-√3/2)²)
z = √(1/4 + 3/4)
z = √1
z = 1.
Read more on unit circle here: brainly.com/question/9797740
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I don't know what 'which of the following' is referring to, but the line has a positive slope, goes through the origin, and has a slope of 2/3.
Answer:
17 1/2
Step-by-step explanation:
17 2/4 is the given and 2/4 is equivalent to one half so the answer is 17 1/2.
Hopefully you understand it now.
The first term in our arithmetic sequence = 13
The common difference of our arithmetic sequence = 17 - 13 = 4
The formula for finding an equation for any arithmetic sequence is a(n) = A + B(n - 1)
A = the first term
B = the common difference.
Let's plug our numbers in.
a(n) = 13 + 4(n - 1)
Let's check to make sure we're correct.
a(1) = 13 + 4(1 - 1) = 13 + 4(0) = 13 + 0 = 13
a(2) = 13 + 4(2 - 1) = 13 + 4(1) = 13 + 4 = 17
That verifies that our formula is correct.
In conclusion,
a(n) = 13 + 4(n - 1)