A ball is thrown from an initial height of 3 feet with an initial upward velocity of 38 ft/s. The ball’s height h (in feet) afte
r t seconds is given by the following.
H=3+38t-16t^2
Find all values of t for which the ball’s height is 17 feet.
Round your answer to the nearest hundredth. (If there is more than one answer, use the “or” button.)
H=3+38t-16t^2
Find all values of t for which the ball’s height is 17 feet.
Round your answer to the nearest hundredth. (If there is more than one answer, use the “or” button.)
1 answer:
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Answer:
Step-by-step explanation:
So first, let's get rid of the parentheses. We can multiply it out to get . We know that the square root of 16 is ±4, so now our equation is ±4 -
=11. I'm guessing since the problem only has one solution it's most likely only positive 4, so let's revise our equation to 4 -
=11. We can use inverse operations to make the a little easier to solve: -7=
. We divide both sides by
to get
, which we can rationalize (remove the square root from the denominator so that it's a proper answer) by multiplying by
(which is equal to one so we can use it) which is equal to
. Let's finish this by simplifying it.
(2x
). We can simplify it further by simplifying the 2, making it
.
Hope this wasn't too confusing! I'll answer any questions.