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2 years ago

10

A ball is thrown from an initial height of 3 feet with an initial upward velocity of 38 ft/s. The ball’s height h (in feet) afte

r t seconds is given by the following.
H=3+38t-16t^2

Find all values of t for which the ball’s height is 17 feet.

Round your answer to the nearest hundredth. (If there is more than one answer, use the “or” button.)

1 answer:

Tema [17]2 years ago

8 0

Answer:

1.92 or 4.56 answer when rounded to 100th

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FInd the X- and the Y-intercept of the line.

Maurinko [17]

A. You divide 1 (infront of x) by 12 to get 12. You divide -6 by 12 to get -2 for the y intercept.

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2 years ago

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What is the sum of the probability of drawing a green marble and the probability of not drawing a green marble?

andrey2020 [161]

Yo sup??

the answer is 1 because

P(E)+P(E')=1

where E is the event and

E' is the complement of the event

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3 years ago

Evaluate the value of x to 1 d.p<br><br><br> Thank you

Keith_Richards [23]

Answer:

value of x = 2.8

Step-by-step explanation:

By law of cosines,

${a}^{2} = {b}^{2} + {c}^{2} - 2 \times b \times c \times cos(100) \\ {x}^{2} = {13}^{2} + {10}^{2} - (2 \times 13 \times 10 \times cos100) \\ = 169 + 100 - 260 \times 0.862 \\ = 269 - 260 \times 0.862 \\ = 7.758 \\x = \sqrt{7.758 } \\ = 2.785 \\ = approx \: 2.8$

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2 years ago

Use technology or a z-score table to answer the question.

Alik [6]

Answer:

The second choice: Approximately $65.2\%$ of the pretzel bags here will contain between 225 and 245 pretzels.

Step-by-step explanation:

This explanation uses a z-score table where each $z$ entry has two decimal places.

Let $\mu$ represent the mean of a normal distribution of variable $X$ . Let $\sigma$ be the standard deviation of the distribution. The z-score for the observation $x$ would be:

$\displaystyle z = \frac{x - \mu}{\sigma}$ .

In this question,

$\mu = 240$ .
$\sigma = 9.3$ .

Calculate the z-score for $x_1 = 225$ and $x_2 = 245$ . Keep in mind that each entry in the z-score table here has two decimal places. Hence, round the results below so that each contains at least two decimal places.

$\begin{aligned} z_1 &= \frac{x_1 - \mu}{\sigma} \\ &= \frac{225 - 240}{9.3} \approx -1.61\end{aligned}$ .

$\begin{aligned} z_2 &= \frac{x_2 - \mu}{\sigma} \\ &= \frac{245 - 240}{9.3} \approx 0.54\end{aligned}$ .

The question is asking for the probability $P(225 \le X \le 245)$ (where $X$ is between two values.) In this case, that's the same as $P(-1.61 \le Z \le 0.54)$ .

Keep in mind that the probabilities on many z-table correspond to probability of $P(Z \le z)$ (where $Z$ is no greater than one value.) Therefore, apply the identity $P(z_1 \le Z \le z_2) = P(Z \le z_2) - P(Z \le z_1)$ to rewrite $P(-1.61 \le Z \le 0.54)$ as the difference between two probabilities:

$P(-1.61 \le Z \le 0.54) = P(Z \le 0.54) - P(Z \le -1.61)$ .

Look up the z-table for $P(Z \le 0.54)$ and $P(Z \le -1.61)$ :

$P(Z \le 0.54)\approx 0.70540$ .
$P(Z \le -1.61) \approx 0.05370$ .

$\begin{aligned}& P(225 \le X \le 245) \\ &= P\left(\frac{225 - 240}{9.3} \le Z \le \frac{245 - 240}{9.3}\right)\\&\approx P(-1.61 \le Z \le 0.54) \\ &= P(Z \le 0.54) - P(Z \le -1.61)\\ &\approx 0.70540 - 0.05370 \\& \approx 0.65.2 \\ &= 65.2\% \end{aligned}$ .

3 0

3 years ago

Find the angle between u = (8.- 3) and v = (-3,- 8) Round to the nearest tenth of a degree.

Nimfa-mama [501]

Answer:

<h2>90°</h2>

Step-by-step explanation:

First you must calculate the module or the magnitude of both vectors

The module of u is:

$|u|=\sqrt{(8)^2 + (-3)^2} \\\\|u|=\sqrt{64 + 9}\\\\|u|=8.544$

The module of v is:

$|v|=\sqrt{(-3)^2 + (-8)^2} \\\\|u|=\sqrt{9 + 64}\\\\|u|=8.544$

Now we calculate the scalar product between both vectors

$u*v = 8*(-3) + (-3)*(-8)\\\\u*v = -24+ 24=0$

Finally we know that the scalar product of two vectors is equal to:

$u*v = |u||v|*cos(\theta)$

Where $\theta$ is the angle between the vectors u and v. Now we solve the equation for $\theta$

$0 = 8.544*8.544*cos(\theta)\\\\0 = cos(\theta)\\\\\theta= arcos(0)\\\\\theta=90\°$

the answer is 90°

Whenever the scalar product of two vectors is equals to zero it means that the angle between them is 90 °

5 0

3 years ago

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