49.50 increased with 55% discount of 51%=

Please help sorry I’m dumb

Nady [450]

The answer is x = 18

6 0

3 years ago

How many tenths is 0.4

Salsk061 [2.6K]

0.4 has 4 tenths

Look at 0.4 as 0.40

Divide the 40 by 10 and get 4

-Hope this helped!

8 0

3 years ago

Read 2 more answers

Find the volume v of the described solid s. the base of s is an elliptical region with boundary curve 4x2 + 9y2 = 36. cross-sect

Tasya [4]

$4x^2+9y^2=36\iff\dfrac{x^2}9+\dfrac{y^2}4=1$

defines an ellipse centered at $(0,0)$ with semi-major axis length 3 and semi-minor axis length 2. The semi-major axis lies on the $x$ -axis. So if cross sections are taken perpendicular to the $x$ -axis, any such triangular section will have a base that is determined by the vertical distance between the lower and upper halves of the ellipse. That is, any cross section taken at $x=x_0$ will have a base of length

$\dfrac{x^2}9+\dfrac{y^2}4=1\implies y=\pm\dfrac23\sqrt{9-x^2}$
$\implies \text{base}=\dfrac23\sqrt{9-{x_0}^2}-\left(-\dfrac23\sqrt{9-{x_0}^2}\right)=\dfrac43\sqrt{9-{x_0}^2}$

I've attached a graphic of what a sample section would look like.

Any such isosceles triangle will have a hypotenuse that occurs in a $\sqrt2:1$ ratio with either of the remaining legs. So if the hypotenuse is $\dfrac43\sqrt{9-{x_0}^2}$ , then either leg will have length $\dfrac4{3\sqrt2}\sqrt{9-{x_0}^2}$ .

Now the legs form a similar triangle with the height of the triangle, where the legs of the larger triangle section are the hypotenuses and the height is one of the legs. This means the height of the triangular section is $\dfrac4{3(\sqrt2)^2}\sqrt{9-{x_0}^2}=\dfrac23\sqrt{9-{x_0}^2}$ .

Finally, $x_0$ can be chosen from any value in $-3\le x_0\le3$ . We're now ready to set up the integral to find the volume of the solid. The volume is the sum of the infinitely many triangular sections' areas, which are

$\dfrac12\left(\dfrac43\sqrt{9-{x_0}^2}\right)\left(\dfrac23\sqrt{9-{x_0}^2}\right)=\dfrac49(9-{x_0}^2)$

and so the volume would be

$\displaystyle\int_{x=-3}^{x=3}\frac49(9-x^2)\,\mathrm dx$
$=\left(4x-\dfrac4{27}x^3\right)\bigg|_{x=-3}^{x=3}$
$=16$

6 0

3 years ago

How do you find the quotient of 45/9

pishuonlain [190]

The quotient of the given fraction 45/9 is 5.

<h3>What is division?</h3>

The division is one of the four basic operations of arithmetic, which are the methods by which numbers are combined to form new numbers.
Addition, subtraction, and multiplication are the other operations.
At the most basic level, the division of two natural numbers is the process of calculating the number of times one number is contained within another.

Quotient:

A quotient is a quantity produced by the division of two numbers in arithmetic.
The quotient is widely used in mathematics and is also known as the integer part of a division, a fraction, or a ratio.

So, the quotient of 45/9 is 5 as:
45 ÷ 9 = 5

(Refer to the picture given below for working)

Therefore, the quotient of the given fraction is 5.

Know more about division here:

brainly.com/question/25289437

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