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enot [183]
3 years ago
7

HELP FAST 10 POINTS

Mathematics
1 answer:
Nat2105 [25]3 years ago
5 0

Answer:

y=1/5x-3

Step-by-step explanation:

Start by finding the slope:

Slope = (y₂-y₁)/(x₂-x₁)

Now we plug in the coordinates:

Slope = (12-(-3))/(-3-0)=(12+3)/(-3)=15/-3=-5

The slope intercept equation would be

y=mx+b

Slope is m and y-intercept is b. x and y and the x and y-coordinates.

Now we plug in one of the x and y coordinate pairs into the equation:

-3=-5(0)+b

b=-3

So the equation of the line would be

y=-5x-3

<em>But the slope of a perpendicular line is the negative reciprocal of the original equation</em>

So...

y=1/5x-3

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Which of the following is a point slope equation of the line below (10,5)(2,2)
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\frac{5-2}{10-2} = \frac{3}{5} as our slope. Keeping in mind that it does not matter which point is point 1 and which point is point 2, we go back to  y-y₁=m(x-x₁) and plug a point in (I'll be using (10,5)). Note that x₁, m,  and y₁ need to be plugged in, but x and y stay that way so that you can plug x or y values into the formula to find where exactly it is on the line. Thus, we have our point slope equation to be y- 5= \frac{3}{5} (x-10)

Feel free to ask further questions!
7 0
3 years ago
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