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Valentin [98]
3 years ago
6

Rectangle ABCD is translated (x + 2 y - 3) and then rotated 180° about the origin. Complete the table to show the locations of A

'. B', C', and D' after both transformations.
B
0
3
2
D
A-51) A' ?
B (-5,3) B 2
C (-1.3) C" ?
D--11)
D' ?
A(-2,-3), B' (0-3), C (0.1), D'(-2.1)

Mathematics
1 answer:
katen-ka-za [31]3 years ago
4 0

Answer:

A

Step-by-step explanation:

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Write the next whole number after 6748nine in the base-nine system.
ale4655 [162]

Answer:

Step-by-step explanation:

6748_9 = 6 *(9^3) + 7 * 9^2 + 4 * 9^1 + 8 * 9 ^ 0 = 4994_{10}

Hence, on base 10, the next whole number is 4995 and if we convert back to base 9, we will have

6* 9^3 + 7*9^2 + 5*9*1 = 4374 + 576+45 = 4995_{10}

Therefore, the number on base 9 will be 6750

7 0
3 years ago
Please help i need it
Dima020 [189]

Answer:

Mei is correct because -9 is to the left of -3 on the number line.

Step-by-step explanation:

This is because -9 is LESS than -3, when you add or subtract using negative numbers, such as 7-9, you get -2. However when you subtract 7-13, you get -6. Because you subtracted a greater number from 7, your answer is -6 is LESS than -2. This is the same with inequalities, greater negative numbers will always be smaller and smaller negative numbers will always be greater.

Hope this helps!

4 0
11 months ago
Find the sum of the first 47 terms of the following series, to the nearest integer.
Leokris [45]

Answer:

The sum of the first 47 terms of the series, 12, 16, 20, ... S₄₈ is 4,888

Step-by-step explanation:

The given series is;

12, 16, 20, ...,

Therefore, the first term of the series is, a = 12

The common difference of series is found as follows;

The difference between subsequent terms, 12 and 16 is  16 - 12 = 4

The difference between subsequent terms, 16, and 20 is  20 - 16 = 4

Therefore, the common difference, d = 4

The series is therefore an arithmetic projection, AP

The sum of the first 'n' terms of an AP, Sₙ, is given as follows;

S_n = \dfrac{n}{2} \cdot \left [2 \cdot a + (n - 1)\cdot d \right ]

(47/2)*(2*12+(47-1)*4)

The sum of the first 47 terms is therefore given as follows;

S_n = \dfrac{47}{2} \cdot \left [2 \times 12 + (47 - 1)\times 4 \right ] = 4,888

The sum of the first 47 terms of the series, 12, 16, 20, ... S₄₈ = 4,888

5 0
2 years ago
After completing the fraction 8 devided 1/6 Pastel found a quotient of
Rama09 [41]
The answer is 2 be 8/16 is 2
3 0
3 years ago
bonjour quelqu'un peut m'aider Svp c'est pour un exercice de mathématiques . merci en avance . exprimez sous forme de pourcentag
lubasha [3.4K]
1sur10=10% 1sur5=20% 1sur2=50% 4sur5=80%
7 0
3 years ago
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