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jok3333 [9.3K]
2 years ago
11

Find the derivative of sin2X​

Mathematics
2 answers:
murzikaleks [220]2 years ago
7 0

Answer:

2cos2x

Step-by-step explanation:

Using the Chain rule

\frac{d}{dx} (sin2x)

= cos2x × \frac{d}{dx} (2x)

= cos2x × 2

= 2cos2x

inn [45]2 years ago
5 0

Step-by-step explanation:

Derivation using Product rule : -

To find the derivative of f(x) = sin 2x by the product rule, we have to express sin 2x as the product of two functions. Using the double angle formula of sin, sin 2x = 2 sin x cos x. Let us assume that u = 2 sin x and v = cos x. Then u' = 2 cos x and v' = -sin x. By product rule,

f '(x) = uv' + vu'

= (2 sin x) (- sin x) + (cos x) (2 cos x)

= 2 (cos2x - sin2x)

= 2 cos 2x

This is because, by the double angle formula of cos, cos 2x = cos2x - sin2x.

Thus, derivation of sin 2x has been found by using the product rule.

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Answer:

B.) y - 6 = -8/5(x + 2)

Step-by-step explanation:

Remember in order to find the slope intercept form on 2 points, you need these equations: \frac{x_2 -x_1}{y_2 -y_1} and y-y_1=m(x-x_1)

To find the slope, you will need to use the first equation. In this case the equation will look like this: \frac{(-2)-6}{3-(-2)}=-\frac{8}{5}

Then use the second equation, plug in the numbers, and you will get B as your answer

5 0
2 years ago
solo savings bank received an initial deposit of $6000 it kept a percentage of this money in reserve based on the reserve rate a
iogann1982 [59]

Answer:

Reserve rate = 3%

Step-by-step explanation:

Reserve Ratio = Reserve Maintained with Central Bank / Deposit Liabilities × 100

Reserve maintained = $6,000

Deposit liabilities = $200,000

Reserve Rate = Reserve Maintained with Central Bank / Deposit Liabilities × 1000

=$6,000 / $200,000 × 100

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Therefore,

Reserve Rate =3%

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3 years ago
What is the equation of the line?
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That's a vertical line, no slope, so no y=something.  

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3 years ago
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OverLord2011 [107]

Answer:

y = 8

Step-by-step explanation:

Equation of the line that passes through (-2, 8) with a slope of 0, can be written in point-slope form, y - y_1 = m(x - x_1) and also in slope-intercept form, y = mx + b.

Using a point, (-2, 8) and the slope (m), 0, substitute x1 = -2, y1 = 8 and m = 0 in y - y_1 = m(x - x_1).

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y - 8 = 0

Rewrite in slope-intercept form

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(6+6)+(2 with a exponent of one) -1
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