Answer:Given that the graph shows tha the functión at x = 0 is below the y-axis, the constant term of the function has to be negative. This leaves us two possibilities:
y = 8x^2 + 2x - 5 and y = 2x^2 + 8x - 5
To try to discard one of them, let us use the vertex, which is at x = -2.
With y = 8x^2 + 2x - 5, you get y = 8(-2)^2 + 2(-2) - 5 = 32 - 4 - 5 = 23 , which is not the y-coordinate of the vertex of the curve of the graph.
Test the other equation, y = 2x^2 + 8x - 5 = 2(-2)^2 + 8(-2) - 5 = 8 - 16 - 5 = -13, which is exactly the y-coordinate of the function graphed.
Step-by-step explanation:
You have to distribute the 2/3 across the equation.
8/3x+18/3 which is 8/3x+6 so the answer is a
I hope that helps
Answer:
6y=12x+18
Step-by-step explanation:
Y=Mx+b
Answer:
2.56
Step-by-step explanation:
The equation they dive u: d = 16t^2, so in the question they said what's the distance, d, if t = 0.4
So you just have to replace t with 0.4:
d = 16t^2
d = 16(0.4)^2
d = 16(0.16)
d = 2.56
A) First, we need to calculate x. We can do this by doing: 180-(70+50), which is nothing but 60.
Since the largest angle is 60, it means that the side opposite of it is the largest side. Which in this case, side AB.
So the largest side is AB.
Now, let's take a look at the smallest angle which is <B, because AC is the opposite of this angle, it must also be the smallest side.
We're left with angle <50, which is "medium" sized? Obviously, this can just be put in the middle (Side BC)
So, for response A, you should get AC, BC, AB.
Now for problem B, it's the same steps we did above. If you replicate what we did you should get PQ, PR,RQ.
Please let me know how I did.
Happy studying!
