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balandron [24]
3 years ago
7

Desperately need help on question 2 & 3 !

Mathematics
1 answer:
Advocard [28]3 years ago
6 0

13

x=15

because of the other one is the only thing

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In a bag of candy for every 3 chocolate pieces there are 7 sugar pieces. What is the ratio of chocolate pieces to sugar pieces?
zzz [600]
The ratio of chocolate to sugar pieces is 3:7
5 0
3 years ago
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Find k if (x+1) 2x^3+kx^2+1
Viktor [21]
<h2>Question:</h2>

Find k if (x+1) is a factor of 2x³ + kx² + 1

<h2>Answer:</h2>

k = 1

<h2>Step-by-step explanation:</h2>

The factor of a polynomial F(x) is another polynomial that divides evenly into F(x). For example, x + 3 is a factor of the polynomial x² - 9.

<em>This is because;</em>

i. x² - 9 can be written as (x - 3)(x + 3) which shows that both (x - 3) and (x + 3) are factors.

ii. If x = -3 is substituted into the polynomial x² - 9, the result gives zero. i.e

=> (-3)² - 9

=> (9) - 9 = 0

Therefore, if (x + a) is a factor of a polynomial, substituting x = -a into the polynomial should result to zero. This also means that, if x - a is a factor of a polynomial, substituting x = a into the polynomial should give zero.

<em><u>From the question</u></em>

Given polynomial: 2x³ + kx² + 1

Given factor: x + 1.

Since x + 1 is a factor of the polynomial, substituting x = -1 into the polynomial should give zero and from there we can calculate the value of k. i.e

2(-1)³ + k(-1)² + 1 = 0

2(-1) + k(1) + 1 = 0

-2 + k + 1 = 0

k - 1 = 0

k = 1

Therefore the value of k is 1.

3 0
3 years ago
What is the value of 6/1+i?​
just olya [345]

Answer:

6/1+i= 6 + i

Step-by-step explanation:

6 0
3 years ago
The average class size this semester in the business school of a particular university is 38.1 students with a standard deviatio
frosja888 [35]

Answer:

The <em>z</em>-score for a a class with 21 students is <u>-1.33</u>.

Step-by-step explanation:

The <em>z</em>-score of a raw <em>X</em> is computed by subtracting the mean of a distribution from the raw score <em>X</em> and dividing the result by the standard deviation of the distribution.

The <em>z</em>-scores are standardized scores and follow a Standard normal distribution.

Given:

μ = 38.1

σ = 12.9

<em>X</em> = 21

Compute the <em>z</em>-score for the raw score <em>X</em> as follows:

z=\frac{X-\mu}{\sigma} =\frac{21-38.1}{12.9} =-1.32558\approx-1.33

Thus, the <em>z</em>-score for a a class with 21 students is <u>-1.33</u>.

5 0
3 years ago
Solve for x. 4(x + 2) = 48
Elanso [62]
Do distributive property first

4x + 8 = 28
move the 8 over
4x = 20
divide by 4
x = 5
5 0
4 years ago
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