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Georgia [21]
3 years ago
9

Resuelve la siguiente ecuación lineal: 13-4(5x+1)=3(7-5x)-15

Mathematics
1 answer:
Temka [501]3 years ago
4 0

.........................

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Help this is really hard
Agata [3.3K]

(2^8 *3^-5* 6^0)^-2 * ((3^-2)/(2^3))^4 * 2^28

anything to the 0 power is 1

(2^8 *3^-5* 1)^-2 * ((3^-2)/(2^3))^4 * 2^28

using the power of power property to take the power inside

(2^(8*-2) *3^(-5* -2) * (3^-2*4)/(2^3*4) * 2^28

simplify

2^ -16 * 3^10 * 3^-8 /2*12   * 2^28

get rid of the division by making the exponent negative

2^-16 * 3^10 * 3^-8 *2*-12   * 2^28

combine exponents with like bases

2^(-16-12+28) * 3^(10-8)

2^(0) *3^2

anything to the 0 power is 1

1*9

9




5 0
3 years ago
Read 2 more answers
Help me please I need the answers
3241004551 [841]
1- 3/4
2- 64
3- 18
4- 36
5- 10
6- 3/4
7- $4.70
8- <
9- =
10- =
4 0
3 years ago
Trapezoid JKLM is shown below.
Alecsey [184]
B is the answer because you have to math it
5 0
3 years ago
Split 840 into the ratio 2:5
pishuonlain [190]

Answer:

numbers are 3x,2x,5x

so 3x+2x+5x=10x=840

so x=84

so numbers are 252,168,420

7 0
2 years ago
How do i find a formula for "1+3+5+7+......+(2n-1)
nata0808 [166]

Answer:

Step-by-step explanation:

common difference d=3-1=2

first term a=1

an=a+(n-1)d

2n-1=1+(l-1)2

2n-1=1+2l-2

2n-1=2l-1

l=n

(i used l for number of terms)

number of terms=n

S_{n}=\frac{n}{2} (first ~term+last~term)\\=\frac{n}{2} (1+2n-1)\\=n^2

7 0
3 years ago
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