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zalisa [80]
4 years ago
10

What is the value of 3-(-2)?

Mathematics
1 answer:
Akimi4 [234]4 years ago
3 0

Answer:

5

Step-by-step explanation:

The double negatives turn into a positive which makes the problem 3+2 which equals 5.

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Step-by-step explanation:

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3 years ago
Which of the following correctly shows the distributive property?
exis [7]
D
4(x+5) = (4)(x)+(4)(5)
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3 years ago
What is the square and square root of 9x⁸​
adelina 88 [10]

Answer:

square: (9x^8)^2= 81x^16

square root: (9x^8)^1/2 = 3x^4

Step-by-step explanation:

the ^ mean that the following num should be like this ​⁸​

8 0
3 years ago
Suppose that c(x)= (7x^3) - (84x^2) + (22,000x) is the cost of manufacturing x items. Find a production level that will minimise
ra1l [238]

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54

Step-by-step explanation:

4 0
3 years ago
A random sample of 16 one-kilogram sugar packets is obtained and the actual weights of the packets are measured. The sample mean
elena55 [62]

Answer:

The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.

Step-by-step explanation:

We are in posession of the sample's standard deviation, so we use the student's t-distribution to find the confidence interval.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 16 - 1 = 15

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 35 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.905([tex]t_{995}). So we have T = 2.9467

The margin of error is:

M = T*s = 2.9467*0.058 = 0.171

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 1.053 - 0.171 = 0.882kg

The upper end of the interval is the sample mean added to M. So it is 1.053 + 0.171 = 1.224 kg.

The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.

3 0
3 years ago
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