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mel-nik [20]
2 years ago
11

On the graph of 2x + y = 5 for the value of x between -2 and 3.

Mathematics
1 answer:
harina [27]2 years ago
6 0

Step-by-step explanation:

y = 5 -2x

x : -2 , -1 , 0 , 1 , 2 , 3

y : 9 , 7 , 5 ,3 , 1 , -1

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Please help with my geometry
erma4kov [3.2K]
25 = hypothenuse
14 = opposite
Use SOHCAHTOA
Give O and H, you can use sin
Sin^-1 = 14/25 = 34.0557
Round to hundreds
Solution: 34.06
8 0
3 years ago
A trapezoid in a coordinate plane has vertices (-2,5),(-3,-2),(2,-2),and (1,5) What is the height of the Trapezoid
Shkiper50 [21]
Rise: 7, Run: 0
Rise (on the y-axis); from -2 to 5
Run (x-axis): 0
8 0
3 years ago
Find the zeros K(x) = -x²+ 2x + 15 EXPLAIN EVERY STEP!
Mumz [18]
Take out - 1
k(x) = -1(x^2 - 2x - 15) Now factor what's inside the brackets. The numbers you pick must add to - 2 and multiply to -15. 
When you multiply to -15 you should note that one of the numbers is plus and the other is minus.
(x -  )(x +  ) is the way it looks.
They differ by 2 and the "largest" one is minus. That means your answer is -5 and +3
k(x) = - (x - 5)(x + 3)
Now for the zeros.
x - 5 can be a zero
x - 5 = 0
x = 5

x + 3 = 0
x = - 3
 
5 0
3 years ago
Use the completing the square method to find the roots of 2x^2+3x-15=13 include the steps, it would be greatly appreciated thank
ValentinkaMS [17]

Answer:

The roots are

x1= \frac{-3+\sqrt{233}}{4}

x2= \frac{-3-\sqrt{233}}{4}

Step-by-step explanation:

we have

2x^{2}+3x-15=13

so

Group terms that contain the same variable, and move the constant to the opposite side of the equation

2x^{2}+3x=13+15

2x^{2}+3x=28

Factor the leading coefficient  

2(x^{2}+(3/2)x)=28

Complete the square. Remember to balance the equation by adding the same constants to each side

2(x^{2}+(3/2)x+(9/16))=28+(9/8)

2(x^{2}+(3/2)x+(9/16))=233/8

(x^{2}+(3/2)x+(9/16))=233/16

Rewrite as perfect squares

(x+(3/4))^{2}=233/16

square root both sides

(x+\frac{3}{4})=(+/-)\sqrt{\frac{233}{16}}\\ \\(x+\frac{3}{4})=(+/-)\frac{\sqrt{233}}{4}\\ \\x= -\frac{3}{4}(+/-)\frac{\sqrt{233}}{4}

x1= -\frac{3}{4}(+)\frac{\sqrt{233}}{4}=\frac{-3+\sqrt{233}}{4}

x2= -\frac{3}{4}(-)\frac{\sqrt{233}}{4}=\frac{-3-\sqrt{233}}{4}

6 0
3 years ago
20<br>Rule: yis 1 more than x<br>15<br>13​
aivan3 [116]

Answer:

D-(x + yi) × 1 = (x + yi)

Step-by-step explanation:

5 0
3 years ago
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