Okay so i would do this with a logarithm. 5^(2x) = 28 take the log of both sides log5^(2x) = log28 and because of this log rule: logA^n = nlogA (2x)log5= log28 then divide by log5 on both sides 2x = log28 / log5 and divide by 2 x = (log28 / log5) /2 this can be found with a calculator:
x= about 1.03521... round that to whatever the question says to
