The equation of the hyperbola with directrices at x = ±2 and foci at (5, 0) and (−5, 0) is 
<h3>How to determine the equation of the hyperbola?</h3>
The given parameters are:
- Directrices at x = ±2
- Foci at (5, 0) and (−5, 0)
The foci of a hyperbola are represented as:
Foci = (k ± c, h)
The center is:
Center = (h,k)
And the directrix is:
Directrix, x = h ± a²/c
By comparison, we have:
k ± c = ±5
h = 0
h ± a²/c = ±2
Substitute h = 0 in h ± a²/c = ±2
0 ± a²/c = ±2
This gives
a²/c = 2
Multiply both sides by c
a² = 2c
k ± c = ±5 means that:
k ± c = 0 ± 5
By comparison, we have:
k = 0 and c = 5
Substitute c = 5 in a² = 2c
a² = 2 * 5
a² = 10
Next, we calculate b using:
b² = c² - a²
This gives
b² = 5² - 10
Evaluate
b² = 15
The hyperbola is represented as:
So, we have:
Evaluate
Hence, the equation of the hyperbola is
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<h2>Answer</h2>
C.) 1
<h2>Explanation </h2>
Remember the rules for shifting functions:
shifts the function b units upward
shifts the function b units downward
shifts the function b units to the left
shifts the function b units to the right
Since we want tho shift 
5 units to the right, we are using the rule: shifts the function b units to the right; in other words, we need to subtract 5 units to the input of the function:
But notice that there is already a negative sign in 
, so to get , k must be equal to positive 1.
Answer:
3.0909090909 repeating
=3.09
Step-by-step explanation:
please mark me brainliest if this is right :)
The water tank hold 863.50 
of water.
<h3>What is Volume of cylinder?</h3>
The volume of a cylinder is the number of unit cubes (cubes of unit length) that can be fit into it. It is the space occupied by the cylinder as the volume of any three-dimensional shape is the space occupied by it.
The water tank is in the shape of cylinder whose radius = 5 feet
and, height= 11 feet
Volume of water tank =
= 3.14 * 5 * 5 * 11
= 3.14*25*11
= 863.50
Hence the water tank hold 863.50 of water.
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Your answer is either C or D. But I strongly believe that the answer would possibly be C.
-Anime
