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laiz [17]
3 years ago
15

Pythagoras.someone help

Mathematics
1 answer:
Katarina [22]3 years ago
8 0
It looks like trigonometry rather than Pythagoras to me. So continuing from the green writing...

Sin x =Opp/Hyp
Sin(29)=6/x
X=6/Sin(29)
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If g(x)= x=2 and h(x) = 4 - X, what is the value of (gºh)(-3)?
navik [9.2K]

The required value of (g°h)(-3) is 5.

Step-by-step explanation:

Given,

g(x)= x-2 and h(x) = 4 - x

To find (g°h)(-3)

Now,

(g°h)(x) = g(h(x))

= g(4-x)

= (4-x)-2 = 2-x

So,

(g°h)(-3) = 2-(-3) = 5 [ putting x=-3]

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3 years ago
8-(-5) =<br> What is the answer
shtirl [24]

Answer:

13

Step-by-step explanation:

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Factor by Grouping.
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Answer:

The ac product of 35x^2+41x+12 is <u>420</u>.

The factors of the ac product that add to 41 are <u>20</u> and <u>21</u>.

35x^2+41x+12 = (7x+4)(5x+3)

Step-by-step explanation:

1) The general form of a quadratic is ax^2 + bx + c. Hence, multiplying 35 by 12 gives you the product of ac, which is 420.

2) We need to find two numbers that multiply to 420 and add up to 41 <u>simultaneously</u>. If we pull out the factors of 420, two of them will be 20 and 21, which multiply to 420 as well as add up to 41.

3) Write 41x as a sum.

35x^2+20x+21x+12

Now, we can factor them out by grouping.

35x^2+20x+21x+12\\5x(7x+4)+3(7x+4)

Since, 7x +4 is common in both of the factors, we only take one of the 7x+4 along with 5x and 3.

(7x+4)(5x+3)

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