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PilotLPTM [1.2K]
2 years ago
13

Find the domain and range of the function graphed below.

Mathematics
1 answer:
anyanavicka [17]2 years ago
7 0

domain = [-3 , 1)

range = [-5 , 4]

have a nice day

and this shape ( and that [ matters so be careful.

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Every year after a new car is
slavikrds [6]

Answer: The value of the car after 3 years is $5,333.333

And no, the relationship is not linear, is an exponential decay.

Step-by-step explanation:

We know that every year, the car loses 1/3 of its value.

So if the initial value of the car is V.

After one year, the new value of the car will be:

Value (1 year) = V - (1/3)*V = (2/3)*V

After another year, the value will be:

Value (2 years) = (2/3)*V - (1/3)*(2/3)*V = V*(2/3)^2

Ok, we already can see that this is an exponential decay.

(So no, this is not a linear relationship).

The value equation as a function of the number of years will be:

Value(N) = V*(2/3)^N

Then if the initial cost of a car is $18,000, and we want to know its value after 3 years, we need to replace V by $18,000 and N by 3 in the above equation:

Value(3) = $18,000*(2/3)^3 = $5,333.333

6 0
3 years ago
Find the value of x and m∠HKL.
frosja888 [35]

Answer:

x = 25 degrees   ∠HKL = 102 degrees

Step-by-step explanation:

The whole thing equals 180, since it is a straight angle

The value of HKL is 180 - 78 = 102

So that means 4x + 2 = 102

Subtract 2 from both sides:

4x = 100

Divide both sides by 4:

x = 25

5 0
3 years ago
Write the decimal in standard form. 11-16<br> giving out 5 stars and thanks if its right!
alina1380 [7]

Answer:

11. 67.103

12. 7.25

13. 210.36

14. 10.5

15. 2.348

16. 72.2

hope that helps

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2 years ago
Divide 53 by 10. write the quotient as a mixed number
posledela

\frac{53}{10}  = 5 \frac{3}{10}

Hope this helps. - M
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3 years ago
Which equation matches the graph shown?
Kitty [74]

Answer:

f(x) = -(x+2)(x-1)

Step-by-step explanation:

We know the zeros are at 1 and -2

f(x) = a *(x-b1)(x-b2)  where b1 and b2 are the zeros and a is a constant

f(x) =a(x-1)(x- -2)

f(x) =a(x-1)(x+2)

We know that a must be negative since the parabola opens down so

The only choice is choice D where a = -1

f(x) = -(x+2)(x-1)

3 0
3 years ago
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