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Shtirlitz [24]
3 years ago
15

If a=bc-d, find d given that a=-16, b=3, c=5

Mathematics
1 answer:
Andrews [41]3 years ago
6 0

Answer:

<h2>d = 31</h2>

Step-by-step explanation:

a = bc - d

Substitute a = -16, b = 3 and c = 5:

-16 = (3)(5) - d

-16 = 15 - d              <em>subtract 15 from both sides</em>

-16 - 15 = 15 - 15 - d

-31 = -d             <em>change the signs</em>

31 = d

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<img src="https://tex.z-dn.net/?f=5x-4%2B2%28x-4%29%3D16" id="TexFormula1" title="5x-4+2(x-4)=16" alt="5x-4+2(x-4)=16" align="ab
mariarad [96]

Answer:

\boxed{x = 4}

Step-by-step explanation:

=> 5x-4+2(x-4) = 16

Expanding the brackets

=> 5x-4+2x-8 = 16

Combining like terms

=> 5x+2x-4-8 = 16

=> 7x - 12 = 16

Adding 12 to both sides

=> 7x = 16+12

=> 7x = 28

Dividing both sides by 7

=> x = 4

3 0
3 years ago
Read 2 more answers
Use the vertical line test to determine if the relation {(–6, –2), (–2, 6), (0, 3), (3, 5)} is a function
hammer [34]

Answer: Its a function

Step-by-step explanation:

6 0
3 years ago
What is the linear function equation represented by the graph?
igor_vitrenko [27]

Look at the picture.

The point-slope form of a line:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (0, 1) and (2, 0). Substitute:

m=\dfrac{0-1}{2-0}=\dfrac{-1}{2}=-\dfrac{1}{2}\\\\y-1=-\dfrac{1}{2}(x-0)\\\\y-1=-\dfrac{1}{2}x\qquad|+1\\\\y=-\dfrac{1}{2}x+1

Answer: f(x)=-\dfrac{1}{2}x+1

5 0
3 years ago
Can someone please check my answer !!!
Verdich [7]

Answer:

its actually the one on the top right

Step-by-step explanation:

Hope it helps ;)

let me know

7 0
3 years ago
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I need a little help here...
lilavasa [31]
So the mean without 894 would be 52.57 
with the 894, the mean would be 157.75
idk what your options are, but there ya go
5 0
3 years ago
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