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damaskus [11]
3 years ago
10

One angle of a triangle measures 120°. The other two angles are in a ratio of 5:7. What are the measures of those two angles

Mathematics
1 answer:
natta225 [31]3 years ago
3 0
5x= one angle measure
7x= second angle measure
120°= third angle

Triangles equal 180°. Add the angles above to total 180°. Find x to find two two unknown angles.

5x + 7x + 120°= 180°
combine like values

12x + 120= 180
subtract 120 from both sides

12x= 60
divide both sides by 12

x= 5

ONE ANGLE MEASURE
5x= 5(5)= 25°

SECOND ANGLE MEASURE
7x= 7(5)= 35°

CHECK:
25° + 35° + 120°= 180°
180°= 180°


ANSWER: The measures of the two angles are 25° and 35°.

Hope this helps! :)
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3 0
3 years ago
The formula T= 2pi sqrt(L/32) relates the time, T, in seconds for a pendulum with the length, L, in feet, to make one full swing
tester [92]

The length of pendulum is 2.485 feet

<h3><u><em>Solution:</em></u></h3>

Given that,

The formula T= 2pi sqrt(L/32) relates the time, T, in seconds for a pendulum with the length, L, in feet, to make one full swing back and forth

<u><em>Therefore, the given formula is:</em></u>

T=2\pi \sqrt{\frac{L}{32} }

We have to find the length of pendulum that makes one full swing in 1.75 seconds

So the modify the given equation to find "L"

T=2\pi \sqrt{\frac{L}{32} }\\\\ \sqrt{\frac{L}{32} }=\frac{T}{2 \pi}\\\\\text{Taking square root on both sides }\\\\\frac{L}{32} = \frac{T^2}{4 \pi^2}\\\\L = \frac{T^2}{4 \pi^2} \times 32\\\\L = \frac{T^2}{\pi^2 } \times 8

Substitute T = 1.75 seconds and \pi = 3.14

L = \frac{1.75^2}{3.14 \times 3.14} \times 8\\\\L = \frac{3.0625}{9.8596} \times 8\\\\L = 2.485

Thus length of pendulum is 2.485 feet approximately

7 0
4 years ago
Pamela took a total of 27 quizzes over the course of 9 weeks. After attending 10 weeks of school this quarter, how many quizzes
shepuryov [24]

Answer:

30

Step-by-step explanation:

27 diviend by 9 = 3 so 27 +3 = 30.

3 0
3 years ago
Least to greatest 1.3, -3/2, -1.2, 1 1/2
lbvjy [14]
1. -3/2
2. -1/2
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3 years ago
What two rational expressions sum to 2x+3/x^2-5x+4
Anni [7]

Answer:

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}

Step-by-step explanation:

Given the rational expression: \frac{2x + 3}{x^2 - 5x + 4}, to express this in simplified form, we would need to apply the concept of partial fraction.

Step 1: factorise the denominator

x^2 - 5x + 4

x^2 - 4x - x + 4

(x^2 - 4x) - (x + 4)

x(x - 4) - 1(x - 4)

(x- 1)(x - 4)

Thus, we now have: \frac{2x + 3}{(x- 1)(x - 4)}

Step 2: Apply the concept of Partial Fraction

Let,

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}

Multiply both sides by (x - 1)(x - 4)

\frac{2x + 3}{(x- 1)(x - 4)} * (x - 1)(x - 4) = (\frac{A}{x- 1} + \frac{B}{x - 4}) * (x - 1)(x - 4)

2x + 3 = A(x - 4) + B(x - 1)

Step 3:

Substituting x = 4 in 2x + 3 = A(x - 4) + B(x - 1)

2(4) + 3 = A(4 - 4) + B(4 - 1)

8 + 3 = A(0) + B(3)

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\frac{11}{3} = B

B = \frac{11}{3}

Substituting x = 1 in 2x + 3 = A(x - 4) + B(x - 1)

2(1) + 3 = A(1 - 4) + B(1 - 1)

2 + 3 = A(-3) + B(0)

5 = -3A

\frac{5}{-3} = \frac{-3A}{-3}

A = -\frac{5}{3}

Step 4: Plug in the values of A and B into the original equation in step 2

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}

7 0
3 years ago
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