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klasskru [66]
3 years ago
7

“If x is a multiple of 2, then it is a multiple of 10.” Is this statement true or false? If it is false, provide a counterexampl

e.
Mathematics
2 answers:
damaskus [11]3 years ago
5 0

Answer:

Its true

Step-by-step explanation:

Because its 2,4,6,8,10

Simora [160]3 years ago
4 0

Answer:

True

Step-by-step explanation:

2 is a multiple of 10 because you can easily count by 2 all the way to 10

Sorry if this answer is wrong

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Lucy works as a tutor for $7 an hour and as a waitress for $12 an hour. This month, she worked a combined total of 86 hours at h
KonstantinChe [14]
<h3>Answer:   7t + 12(86-t)</h3>

==========================================================

Explanation:

  • t = number of hours she worked as a tutor
  • 86-t = number of hours she worked as a waitress

The two expressions mentioned add to 86, to indicate the total number of hours for both jobs combined.

  • 7t = amount earned as a tutor
  • 12(86-t) = amount earned as a waitress

We multiply the number of hours by the wage per hour to get the amount earned per job.

Lastly, we add those two subtotals to get the grand total earned

7t + 12(86-t)

Optionally you can distribute the 12 through and combine like terms. I'll leave it like this because I think it's more descriptive to show the two amounts earned from each job.

If you wanted to simplify 7t+12(86-t), then you would get 1032-5t or -5t+1032

6 0
2 years ago
What is the answer to this question?! answer quick please!
Verizon [17]

Answer:

Step-by-step explanation:

1. 8 seconds

2. 15 quarts

8 0
3 years ago
Complete the equation An tell which property you used (3x10)x8=??x(10x8)
bixtya [17]
 the x's are multiply
that is the associative poprety of multiplcation

so
(ab)c=a(bc)
so
(3x10)x8=3x(10x8)
3 0
4 years ago
You earn the same amount each week at your part-time job. The total amount you earn in 4 weeks is $460. How much do you earn per
almond37 [142]
$115
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3 0
3 years ago
Read 2 more answers
Prove (cosx+cosy)^2+(sinx-siny)^2 = 2+2cos(x+y)
hram777 [196]
<span>Here you go:
1) Applying (a + b)² = a² + b² + 2ab, 
(cosx + cosy)² = cos²x + cos²y + 2cos(x)*cos(y) and 
(sinx + siny)² = sin²x + sin²y + 2sin(x)*sin(y) 

2) ==> (cosx + cosy)² + (sinx + siny)² =  
= (cos²x + sin²x) + (cos²y + sin²y) + 2{cos(x)cos(y) + sin(x)sin(y)} 
= 2 + 2{cos(x - y)} = 2[1 + cos(x - y)]  
= 2*2cos²{(x - y)/2} [Multiple angle identity, 1 + cos(2A) = 2cos²A] 
= 4*cos²{(x - y)/2} [Proved]</span>
7 0
3 years ago
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