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icang [17]
3 years ago
6

Need help! I will give brainless to person who helps

Mathematics
2 answers:
Jobisdone [24]3 years ago
7 0

Answer:

1. X-intercept

Step-by-step explanation:

Cerrena [4.2K]3 years ago
3 0

Answer:

quadranttwo

linear

Step-by-step explanation:

1 across

quadranttwo

14 across

linear

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For what value(s) of k will the relation not be a function?<br> A = {(3k−4, 16), (4k, 32)}
KiRa [710]

We won't have a function if for same value of x in (x,y) we get different values y.

So first step: figure out k so that the first coordinate (x) is the same:

3k-4=4k    | solve for k

k = -4

no check the values y for the elements of the relation

x = 3k-4 = -12-4=-16

so at -16 we get (-16,16) and (-16, 32), which mean for k=-4 the relation is not a function.

Let me know if you have any questions.


7 0
3 years ago
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Which function has real zeros at x = 3 and x = 7
iren2701 [21]

Answer:

7

Step-by-step explanation:

okay

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3 years ago
What is the correct sum of 2.34 and 128.8
jekas [21]

Answer:

131.14

Step-by-step explanation:

Hope this helps!! Good luck!!

6 0
3 years ago
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1 point
Dovator [93]

Answer:

16,800

Step-by-step explanation:

350 * 49 = 16,800

3 0
2 years ago
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The area of a room is 600 square feet. The length is (x + 5) feet and the width is (x + 4) feet. Find the dimensions of the room
tangare [24]
I'm going to assume that the room is a rectangle.

The area of a rectangle is A = lw, where l=length of the rectangle and w=width of the rectangle. 

You're given that the length, l = (x+5)ft and the width, w = (x+4)ft. You're also told that the area, A = 600 sq. ft. Plug these values into the equation for the area of a rectangle and FOIL to multiply the two factors:
A = lw\\&#10;600 = (x+5)(x+4)\\&#10;600 =  x^{2} + 9x + 20&#10;

Now subtract 600 from both sides to get a quadratic equation that's equal to zero. That way you can factor the quadratic to find the roots/solutions of your equation. One of the solutions is the value of x that you would use to find the dimensions of the room:
600 = x^{2} + 9x + 20\\&#10;x^{2} + 9x - 580 = 0\\&#10;(x + 29)(x - 20) = 0\\&#10;x + 29 = 0, \:\: x - 20 = 0\\&#10;x = -29, x = 20

Now you know that x could be -29 or 20. For dimensions, the value of x must give you a positive value for length and width. That means x can only be 20. Plugging x=20 into your equations for the length and width, you get:
Length = x + 5 = 20 + 5 = 25 ft.
Width = x + 4 = 20 + 4 = 24 ft.

The dimensions of your room are 25ft (length) by 24ft (width).
8 0
3 years ago
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