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2 years ago

I need help with this please

Mathematics

1 answer:

DiKsa [7]2 years ago

6 0

I = prt
I = 4,658 • 0.07 • 12
I = $3912.72
Hope this helped

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Students of the film academy asked a group of random people about their favorite film of all time. The following graph shows the

astraxan [27]

Answer:

The answer would be 25%

Helps this helps!

8 0

3 years ago

What is the average (arithmetic mean) of the first 90 measurements in a certain list of 92 measurements? (1) the average of the

marishachu [46]

The sum of all the measurements is just the average times the number.

$\bar x = \frac{1}{n} \sum_{i=1}^n x_i$

$\sum_{i=1}^n x_i = n \bar x$

So if the average of all 92 is 7 the sum of those is $92 \times 7$

The average of the last two is 7.2 so their sum is $2 \times 7.2$

That means the sum of the first 90 is $92 \times 7 - 2 \times 7.2$

so the average of the first 90 is

$\dfrac{92 \times 7 - 2 \times 7.2}{90} = 6.99556$ cm

7 0

3 years ago

PLEASE I NEED HELP WITH THIS

Ber [7]

Given:

The figure of a circle.

To find:

The measure of arc AD and measure of each arc.

Solution:

The measure of arc is equal to the central angle of that arc.

The central angle of arc AD is 105 degrees. So,

$m(arc(AD))=105^\circ$

The central angle of arc BC is 35 degrees. So,

$m(arc(BC))=35^\circ$

The central angle of arc CD is 50 degrees. So,

$m(arc(CD))=50^\circ$

The central angle of a complete circle is 360 degrees. So,

$m(arc(AD))+m(arc(BC))+m(arc(CD))+m(arc(AB))=360^\circ$

$105^\circ+35^\circ+50^\circ+m(arc(AB))=360^\circ$

$190^\circ+m(arc(AB))=360^\circ$

$m(arc(AB))=360^\circ-190^\circ$

$m(arc(AB))=170^\circ$

Therefore, the measure of arc AD is 105°, the measure of arc BC is 35°, the measure of arc CD is 50° and the measure of arc AB is 170°

3 0

2 years ago

Which angles shown in the drawing are supplementary

Arte-miy333 [17]

In order to answer this, we need an image to be able to see what they look like.

5 0

3 years ago

You decide to play roulette 4 times, each time betting on red. What is the distribution of X, the number of times you win?

aalyn [17]

<span> 1.
If betting on red, 18/38 = 9/19 chance of winning, so 10/19 chance of losing
Chance of winning 4 times: (9/19)^4 = 6561/130321 =~ 5.034%
Chance of winning 3 times: (9/19)^3 * (10/19) * C(4,1) = 29160/130321 =~ 22.3755%
Chance of winning 2 times: (9/19)^2 * (10/19)^2 * C(4,2) = 48600/130321 =~ 37.2925%
Chance of winning 1 time: (9/19) * (10/19)^3 * C(4,3) = 36000/130321 =~ 27.624%
Chance of winning 0 times: (10/39)^4 = 10000/130321 =~ 76.7336% </span>

3 0

3 years ago

I need help with this please​

I need help with this please