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meriva
2 years ago
8

The top of a 25-foot ladder is sliding down a vertical wall at a constant rate of 3 feet per minute. When the top of the ladder

is 7 feet from the ground, what is the rate of change of the distance between the bottom of the ladder and the wall?.
SAT
1 answer:
zepelin [54]2 years ago
3 0

Answer:7/8 feet per minute

Explanation:

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Based on the calculations, we have the following:

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<u>Given the following data:</u>

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<h3>How to calculate the paper's area.</h3>

Mathematically, the area of the paper is given by this formula:

Area = length \times breadth\\\\Area = 12 \times 8

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A_2= (2 \times \frac{1}{2} \times 2 \times 9) + 2 \times \frac{1}{2} \times 3 \times 6\\\\A_2=18+18\\\\A_2=36\;in^2

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<h3>The altitude of the parallelogram.</h3>

P = base \times altitude\\\\Altitude =\frac{P}{base} \\\\Altitude =\frac{60}{9.22}

Altitude = 6.51 square inches.

Read more on parallelogram here: brainly.com/question/4459854

<u>Complete Question:</u>

A parallelogram is cut out of a 12-inch by 8-inch sheet of paper. There are four right triangle remnants. Two have the dimensions 2 inches by 9 inches, and the other two have the dimensions 3 inches by 6 inches. The resulting parallelogram has a base of approximately 9.22 inches.

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