The distance formula is the radical (x2-x1)2 + (y2-y1)^2. So for the x value, you subtract (-1) from 8. But be careful. It’s not 8-1. IT’S 8-(-1). Which x value, 9 should be squared. Which it is 81. The y value, you subtract 0 from 6. Which you should have 6 as your y value. Then, again you have to squared it. So, 6^2 is 36. Now that you have both of your x and y value, you have to subtract them again. In order to subtract, you subtract the y value from the x value. In other words, 81-36. The answer should be 45. But 45 is irrational. Because it can’t be rational under the radical form. So to simplified it, you have to find a number that is rational enough to get out from the inside of the radical form. The only number that would work is 9 and 5. So rad 9 is rational because it could escape from the inside. Which it’s 3 once it’s out. But, 5 is irrational and can’t go out. As a result, the answer is 3 rad 5. Or the 3 is outside of the radical form and 5 is the inside.
That would be the term 11c2 because like 14c2, 11c2 has a constant, a variable and raised to the power of 2.
Answer:
a) The discriminant of the equation = - 44
b)The nature of the roots will be imaginary.
c) 
Step-by-step explanation:
Here, the given expression is 
or, 
Now the discriminant (D) of a quadratic equation 
D = 
Hence, the discriminant of the equation = - 44
As D< 0, so the roots will be imaginary.
Now,by quadratic formula : 
So, here 
So, either 
or, 
Answer:
d67d6d 34r2
Step-by-step explanation:
d53eududc6ttd5cf
34. x - 3 = 8x + 4
-3 - 4 = 8x - x
-7 = 7x
-7/7 = x
-1 = x
y = x - 3
y = -1 - 3
y = -4
solution is (-1,-4)
===================
35. -6 = -x - 2y
x = -2y + 6
2 + 5x = -2y
2 + 5(-2y + 6) = -2y
2 - 10y + 30 = -2y
32 = -2y + 10y
32 = 8y
32/8 = y
4 = y
2 + 5x = -2y
2 + 5x = -2(4)
2 + 5x = -8
5x = -8 - 2
5x = -10
x = -10/5
x = -2
solution is (-2,4)
==================
36. 4x + 6y = 2000
x + y = 410
==================
37. 4x + 6y = 2000
x + y = 410......multiply by -6
----------------------
4x + 6y = 2000
-6x - 6y = - 2460 (result of multiplying by -6)
--------------------add
-2x = - 460
x = -460/-2
x = 230 <=== tickets in advance